Question

Sonjia bought a combination lock that opens with a 4-digit number created with the numbers 0 through 9. The same digit cannot be used more than once in the combination. If Sonjia wants the last digit to be 7 and the order of the digits matters, how many ways can the remaining digits be chosen?

Answer 1

Answer:

If Sonjia wants to create combination as described, by using the permutation formula, the number of ways for remaining digits should be:

N = (10-1)(9-1)(8-1) = 9 x 8 x 7 = 504 ways

Hope this helps!

:)