Sonjia bought a combination lock that opens with a 4-digit number created with the numbers 0 through 9. The same digit cannot be

Question

2 years ago

11

Sonjia bought a combination lock that opens with a 4-digit number created with the numbers 0 through 9. The same digit cannot be

used more than once in the combination. If Sonjia wants the last digit to be 7 and the order of the digits matters, how many ways can the remaining digits be chosen?

Mathematics

1 answer:

Dominik [7] · Answer 1 · 2022-07-05T09:45:35+03:00

Dominik [7]2 years ago

3 0

Answer:

If Sonjia wants to create combination as described, by using the permutation formula, the number of ways for remaining digits should be:

N = (10-1)(9-1)(8-1) = 9 x 8 x 7 = 504 ways

Hope this helps!

:)