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3 years ago

How to do proportions?

2 answers:

6 0

Solving proportions is simply a matter of stating the ratios as fractions, setting the two fractions equal to each other, cross-multiplying, and solving the resulting equation. You'll probably start out by just solving proportions, like this: Find the unknown value in the proportion: 2 : x = 3 : 9.

Nesterboy [21]3 years ago

3 0

A proportion is just two fractions set equal to each other

So, when solve a proportion, you cross multiply

$\frac{x}{3}$ = $\frac{3}{4}$

So, multilpy the top of the fraction on the left by the bottom of the fraction on the right

x · 4 = 4x

Now, multiply the bottom of the left by the top of the right

3 · 3 = 9

Now, set these two products equal to each other

4x = 9

Divide by 4 to isolate x

x = $\frac{9}{4}$

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Write the following equation in slope-intercept form: y-8= 4(x+10)

tamaranim1 [39]

Answer:

y = 4x + 48

Step-by-step explanation:

Slope intercept form: y = mx + b

y - 8 = 4x + 40

y = 4x + 48

7 0

2 years ago

Read 2 more answers

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

HELP IM IN DESPERATE NEED!!!<br> What is the solution to this system of equations?

Paladinen [302]

[Given]

{ x + y = 6

{ x = y + 4

[Plug-in our x value & solve]

[Given] x + y = 6

[ Plug-in] (y + 4) + y = 6

[Distribute] y + 4 + y = 6

[Combine like terms] 2y + 4 = 6

[Subtract 4 from both sides] 2y = 2

[Divide both sides by 2] y = 1

[Answer]

Third option - (5, 1)

-> You do not need to solve for x since this is the only option that has y = 1, but to solve for x we would do y + 4 = 1 + 4 = 5, so this answer fully checks correctly

Have a nice day!

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- Heather

6 0

2 years ago

A pentagon has angle measures of 12x°, 7x°, 16x°, 9xº, and 10x°. Find the<br> value of x.

Musya8 [376]

Answer:

Step-by-step explanation:

one interior angle in a pentagon is 108^o.

5 interior angles are 540^o.

If we add 12+7+16+9+10, we get 54x=540^o

That means x=10

3 0

3 years ago

AWNERSSS FOR ALLL PLSSSSSSSS 67 pointssss

melomori [17]

Step-by-step explanation:

4) x=(z-y)/2

8) b=(d)/ac

9) x=(-z+4)/y

10) a=(c-3)b

5 0

2 years ago

Read 2 more answers