1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Flura [38]
3 years ago
14

Preliminary preformulation studies for a new candidate drug molecule does not include one of these

Chemistry
1 answer:
devlian [24]3 years ago
7 0

Answer:

Pilot scale up

Explanation:

Preformulation studies are carried out on candidate drug molecules that show sufficient pharmacological promise in animal model(pharma approach).

It involves preliminary study of the properties of a drug which is considered a potentially active ingredient against a particular disease condition.

Scale-up is the term used to refer to the increase in the batch size of a product. This is only done after a drug has been proven successful against the target disease after extensive pilot studies.

Scale-up is the last operation carried out when a drug has passed through all stages. It is not included in preliminary preformulation studies

You might be interested in
Compound that contains a terminal carbonyl?
malfutka [58]

Many compunds have a terminal carbonyl

Aldehyde, Ketone, Carboxylic acid, Amide, Imide, Acid anhydride are the first that come to my mind.

7 0
3 years ago
Since the half-life of 235U (7. 13 x 108 years) is less than that of 238U (4.51 x 109 years), the isotopic abundance of 235U has
Ymorist [56]

Answer:

\mathtt{ t_1-t_2= In(\dfrac{3}{y}) \times \dfrac{7.13 \times 10^8}{In2} \ years}

Explanation:

Given that:

The Half-life of ^{235}U = 7.13 \times 10^8 \ years is less than that of ^{238} U = 4.51 \times 10^9 \ years

Although we are not given any value about the present weight of ^{235}U.

So, consider the present weight in the percentage of ^{235}U to be  y%

Then, the time elapsed to get the present weight of ^{235}U = t_1

Therefore;

N_1 = N_o e^{-\lambda \ t_1}

here;

N_1 = Number of radioactive atoms relating to the weight of y of ^{235}U

Thus:

In( \dfrac{N_1}{N_o}) = - \lambda t_1

In( \dfrac{N_o}{N_1}) =  \lambda t_1 --- (1)

However, Suppose the time elapsed from the initial stage to arrive at the weight of the percentage of ^{235}U to be = t_2

Then:

In( \dfrac{N_o}{N_2}) =  \lambda t_2  ---- (2)

here;

N_2 =  Number of radioactive atoms of ^{235}U relating to 3.0 a/o weight

Now, equating  equation (1) and (2) together, we have:

In( \dfrac{N_o}{N_1}) -In( \dfrac{N_o}{N_2}) =  \lambda( t_1-t_2)

replacing the half-life of ^{235}U = 7.13 \times 10^8 \ years

In( \dfrac{N_2}{N_1})  = \dfrac{In 2}{7.13 \times 10^9}( t_1-t_2)      ( since \lambda = \dfrac{In 2}{t_{1/2}} )

∴

\mathtt{In(\dfrac{3}{y}) \times \dfrac{7.13 \times 10^8}{In2}= t_1-t_2}

The time elapsed signifies how long the isotopic abundance of 235U equal to 3.0 a/o

Thus, The time elapsed is  \mathtt{ t_1-t_2= In(\dfrac{3}{y}) \times \dfrac{7.13 \times 10^8}{In2} \ years}

8 0
3 years ago
a helium balloon has a volume of 2.95 liters at 25 c. the volume of the ballon decreased to 2.25 l after it is placed outside on
OleMash [197]

Answer:

The outside temperature is -45.8°C

Explanation:

When a gas keeps on constant its moles and its pressure, we can assume that volume will be increased or decreased as the T° (absolute T° in K).

V1 / T1 = V2 / T2

2.95L/298K = 2.25L / T2

(2.95L/298K ) . T2 = 2.25L

T2 = 2.25L . 298K / 2.95L

T2 = 227.2K

T°K - 273 = T°C

227.2K - 273 = -45.8°C

3 0
4 years ago
Describe the particle mode of matter. what does the brownian motion tells us about the particles in matter?give other evidence t
svetlana [45]

Answer:

dium (a liquid or a gas). This pattern of motion typically consists of random fluctuations in a particle's position inside a fluid sub-domain, followed by a relocation to another sub-domain. Each relocation is followed by more fluctuations within the new closed volume. This pattern describes a fluid at thermal equilibrium, defined by a given temperature. Within such a fluid, there exists no preferential direction of flow (as in transport phenomena). More specifically, the fluid's overall linear and angular momenta remain null over time. The kinetic energies of the molecular Brownian motions, together with those of molecular rotations and vibrations, sum up to the caloric component of a fluid's internal energy (the Equipartition theorem).

Explanation:

3 0
3 years ago
You hold two magnets together, end to end, and then let go. If the magnets stay together, the magnets are being _____.
Aleksandr-060686 [28]

Answer:

C-attracted.

Explanation:

When two magnets stay together they are being attracted. If they are pushing each other away, they are being repelled.

5 0
4 years ago
Read 2 more answers
Other questions:
  • Horsetail are helpful for treating
    15·1 answer
  • A wave has a wavelength of 1.2 m and a wave speed of 24 m/s. What is the
    8·2 answers
  • 5. Tree sap can be a very concentrated solution of solutes in water. These are mostly sugars, with van’t Hoff factors of 1. The
    12·1 answer
  • A minimumenergy of 7.21x10-19 J is required to produce the photoelectric effect in chromium metal.
    9·1 answer
  • What does the term chemistry mean?
    8·1 answer
  • Please help brainiest is award!!!!!!!!!!!
    10·2 answers
  • A student prepared several aqueous sodium chloride (NaCl) solutions to observe boiling point elevation at various molal concentr
    9·1 answer
  • How many protons does Tin have?<br>A. 50<br>B. 68<br>C. 118​
    10·1 answer
  • How are covelant and ionic bonds different and what types of elements combine to form each?
    13·2 answers
  • 5. What is a chemical equation? What are the essentials of a chemical equation? What information is conveyed by a chemical equat
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!