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baherus [9]
3 years ago
14

Four people weigh a standard mass of 10.00g on the same balance. Which of the following sets of readings suggests measurements t

hat are neither precise nor accurate
Chemistry
1 answer:
Svetach [21]3 years ago
5 0
An example of accurate but not precise would be 3 people weigh a 10g sample. the weights are 0g, 10g, & 20 grams. the scale is way off but the weights average to the right thing.
precise but not accurate would weighing a 10g sample 3 times and getting 5.5, 5.4, & 5.5. they'e all incredibly similar therefore precise but its nowhere near 10, so not accurate. 
neither precise nor accurate would be 3 weights being 10, 20, &30. It averages wrong and is imprecise.
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How would an element on the left side of row 2 of the periodic table differ from an element in the middle of the same row?
maw [93]

Explanation:

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7 0
2 years ago
Read 2 more answers
200.00 grams of an organic compound is known to contain 83.884 grams of carbon, 10.486
Dmitriy789 [7]

Explanation:

Mass of the organic compound = 200g

Mass of carbon = 83.884g

Mass of hydrogen = 10.486g

Mass of oxygen = 18.640g

The mass of nitrogen = mass of organic compound - (mass of carbon + mass of hydrogen + mass of oxygen)

Mass of nitrogen = 200 - (83.884 + 10.486 + 18.64) = 200 - 113.01‬

Mass of nitrogen = 86.99g

The empirical formula of a compound is its simplest formula.

It is derived as shown below;

                        C                   H                O                  N

Mass          83.884             10.486        18.64            86.99

molar

mass                12                    1                  16                14

Moles       83.884/12         10.486/1       18.64/16        86.99/14

                   

                    6.99                 10.49              1.17                6.21

Divide

by

lowest      6.99/1.17         10.49/1.17           1.17/1.17            6.21/1.17

                       6                    9                         1                       5

Empirical formula  C₆H₉ON₅

learn more:

Empirical formula brainly.com/question/2790794

#learnwithBrainly

                 

                               

8 0
3 years ago
What did Kwang Jeon discover when researching amoeba infected by bacteria?
defon
<span>Kwang Jeon observed that Amoeba had been attacked by a bacterial infection, and lots of the Amoeba had died. However, some survived and continued to reproduce. After investigating the remaining Amoeba and their offspring, he noticed they were very healthy. He thought maybe they were able to fight off the bacteria, but instead, he found they were still infected with the bacteria but were not dying. The bacteria were no longer making the Amoeba sick. Then, he killed off the bacteria using antibiotics and was surprised to see that the Amoeba also died. It seemed the Amoeba and bacteria had formed a relationship in which they both needed each other to survive. After researching, Jeon found that the bacteria made a protein that the Amoeba needed to survive. </span>
6 0
2 years ago
If we want to change a gas to its liquid state, should we add or remove energy from the gas?
Nat2105 [25]
You need to lose some energy from your very excited gas atoms. The easy answer is to lower the surrounding temperature. When the temperature drops, energy will be transferred out of your gas atoms into the colder environment. When you reach the temperature of the condensation point, you become a liquid.
5 0
3 years ago
On a mission to a newly discovered planet, an astronaut finds chlorine abundances of 13.85 % for 35Cl and 86.15 % for 37Cl. What
topjm [15]

Answer : The atomic mass of chlorine is, 36.723 amu

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i

As we are given that,

Mass of 35-Cl isotope = 35 amu

Percentage abundance of 35-Cl isotope = 13.85 %

Fractional abundance of 35-Cl isotope = 0.1385

Mass of 37-Cl isotope = 37 amu

Percentage abundance of 37-Cl isotope = 86.15 %

Fractional abundance of 37-Cl isotope = 0.8615

Now put all the given values in above formula, we get:

\text{Average atomic mass }=[(35\times 0.1385)+(37\times 0.8615)]

\text{Average atomic mass }=36.723amu

Therefore, the atomic mass of chlorine is, 36.723 amu

6 0
3 years ago
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