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Ierofanga [76]
2 years ago
11

ASAP pleaseeee i have to submit it noww

Mathematics
2 answers:
Sauron [17]2 years ago
7 0

Answer:

a. 95

b. 86

Step-by-step explanation:

Since you need it quick, no explanation for now.

patriot [66]2 years ago
4 0

Answer:

Length of the garden: 95 m

Width of the window: 86 cm

Step-by-step explanation:

Part A:

We can use the equation for area to find the length of the garden.

Area = Width * Length

If we simply divide both sides of the equation by width, we will be solving for lenght:

\frac{Area}{Width} = Length

Now, plug in the known values for the area and width of the garden:

\frac{6460}{68}=Length

95=Length

Part B:

This time, we'll have to use the equation for perimeter:

Perimeter = [2(Width)]+[2(Length)]

Because we want to know the width, and already know the perimeter and length we can once again use algebra to solve for the width:

Perimeter-[2(Length)] = 2(Width)\\\frac{Perimeter-[2(Length)]}{2} =Width

Now, simply plug in the values for the perimeter and the length and solve:

\frac{370-[2(99)]}{2} =Width\\\\\frac{370-198}{2} =Width\\\\\frac{172}{2}=Width\\\\86=Width

Therefore, the width of the window is 86 cm.

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Abdul flips a weighted coin 64 times and gets 16 tails. Based on experimental probability, how many of the next 40 flips should
sergij07 [2.7K]

Answer:

yes,  Abdul should expect to come up tails.

7 0
3 years ago
What is the slope of the line that passes through the points (8,-6) and (11,-12)? write the answer in simplest form.​
Hatshy [7]

Answer:

y = -2x + 10

Step-by-step explanation:

The equation is y = mx + b

1. Find the slope first.

--> (y2 - y1) / (x2 - x1) = slope

--> (-12 - -6) / (11 - 8) = (-6) / (3) = -2

2. Then, find the y-intercept (b) by plugging one of the points

--> y = -2x + b

--> -6 = -2(8) + b

--> -6 = -16 + b

--> b = 10

3. Combine

--> y = -2x + 10

8 0
2 years ago
Can someone please help me? need this done ASAP!!!!
nataly862011 [7]

Answer:

They are not similar

Step-by-step explanation:

Angles dont match

5 0
3 years ago
Please help, im stressed and under a time limit .
Shalnov [3]

n=9

Step-by-step explanation:

6^10 = 60466176

6^-4 0.00077160493

60466176  x 0.00077160493 = 46655.9994998 , which is the numerator

6^-5 = 0.00012860082

6^2 = 36

0.00012860082  x 36 = 0.00462962952

46655.9994998  / 0.00462962952 = 10077696

6^9 = 10077696

Therefore, n=9

5 0
3 years ago
Find the sum \[\sum_{k = 1}^{2004} \frac{1}{1 + \tan^2 (\frac{k \pi}{2 \cdot 2005})}.\]
vampirchik [111]

Answer:1002

Step-by-step explanation:

\Rightarrow \sum_{k=1}^{2004}\left ( \frac{1}{1+\tan ^2\left ( \frac{k\pi }{2\cdot 2005}\right )}\right )

and 1+\tan ^2\theta =\sec^2\theta

and \cos \theta =\frac{1}{\sec \theta }  

\Rightarrow \sum_{k=1}^{2004}\left ( \cos^2\frac{k\pi }{2\cdot 2005}\right )

as \cos ^2\theta =\cos ^2(\pi -\theta )

Applying this we get

\Rightarrow \sum_{1}^{1002}\left [ \cos^2\left ( \frac{k\pi }{2\cdot 2005}\right )+\cos^2\left ( \frac{(2005-k)\pi }{2\cdot 2005}\right )\right ]

every \thetathere exist \pi -\theta

such that \sin^2\theta +\cos^2\theta =1

therefore

\Rightarrow \sum_{1}^{1002}\left [ \cos^2\left ( \frac{k\pi }{2\cdot 2005}\right )+\cos^2\left ( \frac{(2005-k)\pi }{2\cdot 2005}\right )\right ]=1002                          

6 0
3 years ago
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