Answer:
x = 2
y = -3
z = 4
( 2 , -3, 4 )
Step-by-step explanation:
x + y + z = 3 ---- i
x – y =5 ---- ii
y - z = -7 ---- iii
ii + iii
x - z = -2 ---- iv
i + ii
2x + z = 8 --- v
iv + v
3x = 6
x = 2
x=2 substitute for v
z = 4
x =2 substitute for ii
y = -3
Answer:
F. y = 9.5x + 22.5
Step-by-step explanation:
let the number of shirts be x
For every shirt he pays $9.50 and $22.5 is the additional price
( x - 6)² = x² - 12 x + 36
Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.0166 = 1.66% probability of a sample proportion of 0.59 or less.
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sampling proportions of a proportion p in a sample of size n has mean
and standard error ![s = \sqrt{\frac{p(1 - p)}{n}}](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%7B%5Cfrac%7Bp%281%20-%20p%29%7D%7Bn%7D%7D)
In this problem:
- 1,190 adults were asked, hence
![n = 1190](https://tex.z-dn.net/?f=n%20%3D%201190)
- In fact 62% of all adults favor balancing the budget over cutting taxes, hence
.
The mean and the standard error are given by:
![\mu = p = 0.62](https://tex.z-dn.net/?f=%5Cmu%20%3D%20p%20%3D%200.62)
![s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.62(0.38)}{1190}} = 0.0141](https://tex.z-dn.net/?f=s%20%3D%20%5Csqrt%7B%5Cfrac%7Bp%281%20-%20p%29%7D%7Bn%7D%7D%20%3D%20%5Csqrt%7B%5Cfrac%7B0.62%280.38%29%7D%7B1190%7D%7D%20%3D%200.0141)
The probability of a sample proportion of 0.59 or less is the <u>p-value of Z when X = 0.59</u>, hence:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
By the Central Limit Theorem
![Z = \frac{X - \mu}{s}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7Bs%7D)
![Z = \frac{0.59 - 0.62}{0.0141}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B0.59%20-%200.62%7D%7B0.0141%7D)
![Z = -2.13](https://tex.z-dn.net/?f=Z%20%3D%20-2.13)
has a p-value of 0.0166.
0.0166 = 1.66% probability of a sample proportion of 0.59 or less.
You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213
Answer:
![S = \{PRC, PRI,PAC,PAI,PDC,PDI,BRC, BRI,BAC,BAI,BDC,BDI\}](https://tex.z-dn.net/?f=S%20%3D%20%5C%7BPRC%2C%20PRI%2CPAC%2CPAI%2CPDC%2CPDI%2CBRC%2C%20BRI%2CBAC%2CBAI%2CBDC%2CBDI%5C%7D)
Step-by-step explanation:
Given
![Restaurant = \{P,B\}](https://tex.z-dn.net/?f=Restaurant%20%3D%20%5C%7BP%2CB%5C%7D)
![Movies = \{R,A,D\}](https://tex.z-dn.net/?f=Movies%20%3D%20%5C%7BR%2CA%2CD%5C%7D)
![Post-movie = \{C,I\}](https://tex.z-dn.net/?f=Post-movie%20%3D%20%5C%7BC%2CI%5C%7D)
Required
List out the sample space
To do this, we simply pick 1 item in each category, without repetition.
So, we have:
![S = \{PRC, PRI,PAC,PAI,PDC,PDI,BRC, BRI,BAC,BAI,BDC,BDI\}](https://tex.z-dn.net/?f=S%20%3D%20%5C%7BPRC%2C%20PRI%2CPAC%2CPAI%2CPDC%2CPDI%2CBRC%2C%20BRI%2CBAC%2CBAI%2CBDC%2CBDI%5C%7D)