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Scorpion4ik [409]
3 years ago
7

Make y the subject of each of y-p=m​

Mathematics
1 answer:
Serga [27]3 years ago
6 0

Answer:

y=m+p

Step-by-step explanation:

take the p to the other side.

p crosses = sighn and becomes +

hence ans = y=m+ p

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Tim had $20.00 to spend on 6 pens. After buying them, he had $8.00. How much did each pen cost?
Kazeer [188]
If Tim had $20 to spend on 6 pens, and after buying them he had $8 left, that means that he spent 20 - 8 = $12 dollars on those 6 pens.
This means that to calculate the price of one pen, you just need to divide the money he spent ($12) by the number of pens he bought (6), and that is 12/6 = 2. Each pen cost him <span>$2.</span>
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3 years ago
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If x= 5 and y = 2, work out the value of a) 3x + y<br> b) 2x2<br> c) (x - y)2
Oxana [17]

Answer:

17, 50, 9

Step-by-step explanation:

Hello

We already know the values of x and y, 5 and 2.

All we have to do to figure out a, b, and c, is to plug in those known values.

a) 3x + y

Let's plug in x and y as 5 and 2

3(5) + 2

15 + 2

17

b) 2x^2

2(5)^2

2(25)

50

c) (x - y)^2

(5 - 2)^2

3^2

9

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3 years ago
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I WILL GIVE BRIANLEST TO THE PERSON WHO ANSWER IT WRITE.
kykrilka [37]
The answer to the first part is D
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If discount rate is 12%, the present value of Rs X recieved at the end of each year for the next five years is equal to
myrzilka [38]

Answer:

Present Value = X [\frac{1}{(1 + 0.12)^{1} }  + \frac{1}{(1 + 0.12)^{2} }  + \frac{1}{(1 + 0.12)^{3} }  + \frac{1}{(1 + 0.12)^{4} }  + \frac{1}{(1 + 0.12)^{5} } ]

Step-by-step explanation:

To find - If discount rate is 12%, the present value of Rs X received at the end of each year for the next five years is equal to .... ?

Solution -

We know that, formula for finding the Present vale is given by

Present value = Future value / (1 + r)ⁿ

where r is the rate of interest

and n is Number of periods

Now,

Here in the question, we have

r = 12% = 12/100 = 0.12

n = 5

Also, Given that, we have received Rs X at the end of each year

So,

Present Value = \frac{X}{(1 + 0.12)^{1} }  + \frac{X}{(1 + 0.12)^{2} }  + \frac{X}{(1 + 0.12)^{3} }  + \frac{X}{(1 + 0.12)^{4} }  + \frac{X}{(1 + 0.12)^{5} }

                        = X [\frac{1}{(1 + 0.12)^{1} }  + \frac{1}{(1 + 0.12)^{2} }  + \frac{1}{(1 + 0.12)^{3} }  + \frac{1}{(1 + 0.12)^{4} }  + \frac{1}{(1 + 0.12)^{5} } ]

⇒Present Value = X [\frac{1}{(1 + 0.12)^{1} }  + \frac{1}{(1 + 0.12)^{2} }  + \frac{1}{(1 + 0.12)^{3} }  + \frac{1}{(1 + 0.12)^{4} }  + \frac{1}{(1 + 0.12)^{5} } ]

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3 years ago
Jeremy tracked the temperature as a weather front crossed his region. The temperature rose 12 degrees, fell 27 degrees, and fina
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Answer: -2 degrees Celsius

Step-by-step explanation:

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3 years ago
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