The distance between points
and
can be calculated using formula
![P_1P_2=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.](https://tex.z-dn.net/?f=P_1P_2%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D.)
1.
![AB=\sqrt{(-7-(-11))^2+(8-4)^2}=\sqrt{16+16}=\sqrt{32}=4\sqrt{2}\approx 5.657.](https://tex.z-dn.net/?f=AB%3D%5Csqrt%7B%28-7-%28-11%29%29%5E2%2B%288-4%29%5E2%7D%3D%5Csqrt%7B16%2B16%7D%3D%5Csqrt%7B32%7D%3D4%5Csqrt%7B2%7D%5Capprox%205.657.)
2.
![AC=\sqrt{(-4-(-11))^2+(4-4)^2}=\sqrt{49+0}=\sqrt{49}=7.](https://tex.z-dn.net/?f=AC%3D%5Csqrt%7B%28-4-%28-11%29%29%5E2%2B%284-4%29%5E2%7D%3D%5Csqrt%7B49%2B0%7D%3D%5Csqrt%7B49%7D%3D7.)
3.
![CB=\sqrt{(-7-(-4))^2+(8-4)^2}=\sqrt{9+16}=\sqrt{25}=5.](https://tex.z-dn.net/?f=CB%3D%5Csqrt%7B%28-7-%28-4%29%29%5E2%2B%288-4%29%5E2%7D%3D%5Csqrt%7B9%2B16%7D%3D%5Csqrt%7B25%7D%3D5.)
Then
![P_{ABC}=5.657+7+5=17.657\approx 17.7](https://tex.z-dn.net/?f=P_%7BABC%7D%3D5.657%2B7%2B5%3D17.657%5Capprox%2017.7)
Answer: correct choice is C.
Perpendicular lines will have negative reciprocal slopes. What that means is if u have a slope of 1/2, to find the negative reciprocal, flip the slope and change the sign.......flip 2/1, change the sign -2/1 or just -2. So the negative reciprocal for the slope of 1/2 is -2.
A. y = 1/5x + 3.....slope here is 1/5, so for a perpendicular line, u r gonna need an equation with the slope of -5.....and that would be : y + 3 = -5(x + 2).
B. Parallel lines will have the same slope. y = 5x - 2...the slope here is 5...so a parallel line will have a slope of 5.
y = mx + b
slope(m) = 5
(8,-2)...x = 8 and y = -2
now we sub, we r looking for b, the y intercept
-2 = 5(8) + b
-2 = 40 + b
-2 - 40 = b
-42 = b
so ur parallel equation is : y = 5x -42
Answer:
sure
Step-by-step explanation:
she multiplied it 3 times, so, i dont think 8 should be negative.
Answer:
27
Step-by-step explanation:
The answer is 27, because 9 x 3 = 27 and the smallest number that is the same is 27.
Hope this helps!