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Hunter-Best [27]
3 years ago
8

In a chess tournament, each player plays every other player exactly once. If it is known that 105 games were played, how many pl

ayers were there in the tournament?
Mathematics
1 answer:
diamong [38]3 years ago
3 0

Answer:

15 players played in the chess tournament.

Step-by-step explanation:

When there are 15 players, the first player plays 14 games and step aside.

remaining 14 player

next player plays 13 games. steps aside

remaining 13 players

next player plays 12 games. steps aside

remaining 12 players

next player plays 11 games. steps aside

remaining 11 players

.

.

.

.

Last player plays 1 game and steps aside

remaining 1 player who will not play against himself.

∴ Sum of all games played

= 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 105 games played

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Answer:

I think x = 4.

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3x + x +10 + 5x + 2x + 2 =56

(3x + x + 5x + 2x) + (10 + 2) = 56 (Combine Like Terms)

11x + 12 = 56

11x + 12 = 56

Step 2: Subtract 12 from both sides.

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Step 3: Divide both sides by 11.

11x/11 = 44/11

x = 4

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Graph the equation to solve the system. y=2x+7 1/2y=x+7/2
vlabodo [156]

Given equation is y=2x+7 and \frac{1}{2}y=x+\frac{7}{2}

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Step-by-step explanation:

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