Question

Please help me with this!!!!

Answer 1

Answer:

  1. 64x² -48x +9

  2. x = 8; (8, -62); (-∞, ∞); [-62, ∞)

Step-by-step explanation:

1) The area of a square is the square of the side length.

  A = (8x -3)² = (8x)² +2(8x)(-3) +(-3)²

  A = 64x² -48x +9 . . . . area of the sign

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2) Axis of symmetry:

  x = -b/(2a) = -(-16)/(2(1))

  x = 8 . . . . axis of symmetry

The vertex can be found by adding and subtracting the square of the above value:

  y = x^2 -16x +64 +2 -64

  y = (x -8)^2 -62

Compare this to "vertex form" with vertex (h, k):

  y = (x -h)^2 +k

The vertex is (x, y) = (8, -62).

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The domain is all real numbers, as it is for any polynomial.

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The range is all numbers at and above the vertex.

The range is all numbers greater than or equal to -62.