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3 years ago

11

Stephen and Shane are twins. They came up with a math puzzle . Stéphen says he is (5x + 4) years old, and Shane says he is (10x

- 3) years old. What is the value of ? What are their ages?

1 answer:

Cloud [144]3 years ago

7 0

We can assume that 5x+4 = 10x-3 if they are twins and the same age, so take 5x from both sides to get 4=5x-3, add 3 to get 7=5x, and divide by 5, so x=1.4. We can then sub this value for x back into one of the equations, so (5x1.4)+4 to see that they are both 11 years old.

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in 2013 January there were 360 pupils in school the ratio of boots to girls was 5:4 in February 18 boys were admitted in school

anyanavicka [17]

Answer:

218

Step-by-step explanation:

this is ratio.

5+4=9. which is the ratio you add it.

5/9×360=200

therefore the number of boys in school during 2013 january is 200 plus admitted boys in February is 200+18=218.

therefore the number of boys in school from january to february is 218.

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the post office sold 900 stamps yesterday.1/4 of the stamps are postcard stamps. How many postcard stamps did they sell?

Lorico [155]

1/4 = .25 or 25%
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3 years ago

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tamaranim1 [39]

Answer:

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Step-by-step explanation:

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- Polynomial Functions -For each function, state the vertex; whether the vertex is a maximum or minimum point; the equation of t

vladimir2022 [97]

EXPLANATION

Given the function f(x) = (x-6)^2 + 1

$\mathrm{The\: vertex\: of\: an\: up-down\: facing\: parabola\: of\: the\: form}\: y=ax^2+bx+c\: \mathrm{is}\: x_v=-\frac{b}{2a}$

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

$=x^2-12x+37$ $\mathrm{The\: parabola\: params\: are\colon}$ $a=1,\: b=-12,\: c=37$ $x_v=-\frac{b}{2a}$ $x_v=-\frac{\left(-12\right)}{2\cdot\:1}$ $\mathrm{Simplify}$ $x_v=6$ $y_v=6^2-12\cdot\: 6+37$

Simplify:

$y_v=1$

$\mathrm{Therefore\: the\: parabola\: vertex\: is}$ $\mleft(6,\: 1\mright)$ $\mathrm{If}\: a$ $\mathrm{If}\: a>0,\: \mathrm{then\: the\: vertex\: is\: a\: minimum\: value}$ $a=1$ $\mathrm{Minimum}\mleft(6,\: 1\mright)$ $\mathrm{For\: a\: parabola\: in\: standard\: form}\: y=ax^2+bx+c\: \mathrm{the\: axis\: of\: symmetry\: is\: the\: vertical\: line\: that\: goes\: through\: the\: vertex}\: x=\frac{-b}{2a}$

Expanding (x-6)^2 + 1 by applying the Perfect Square Formula:

$y=x^2-12x+37$ $\mathrm{Axis\: of\: Symmetry\: for}\: y=ax^2+bx+c\: \mathrm{is}\: x=\frac{-b}{2a}$ $a=1,\: b=-12$ $x=\frac{-\left(-12\right)}{2\cdot\:1}$ $\mathrm{Refine}$

Axis of simmetry : x=6

The quadratic function has the same shape than the parent function y=x^2 because there is NOT a coefficient within x.

3 0

1 year ago