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3 years ago

Consider the line y =

Mathematics

1 answer:

IRISSAK [1]3 years ago

6 0

Answer:

not sure

Step-by-step explanation:

....... osrry.

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HELP— graphing<br> get marked brainliest

34kurt

Answer: Point C

You can see on the graph that it’s -3 (3 to the left of 0) and it’s -2 (2 below the x axis)

4 0

4 years ago

The area of Brian’s rectangular garden, in square feet, can be found by using the expression 6(2x + 5y). Use the distributive pr

GalinKa [24]

The equivalent expression is 12x+30y and the area is 156 ft².

Using the distributive property, we have
6(2x+5y)
6*2x+6*5y
12x+30y

If x=3 and y=4,
12*3+30*4
36+120
156

5 0

4 years ago

25 is 12% of what number? How do I find the answer?

Irina18 [472]

25x12% is 3
I hope I helped!

6 0

4 years ago

Read 2 more answers

State the commutative property of multiplication, and provide an example using two different numbers.

attashe74 [19]

Answer:

The commutative property of multiplication states that the numbers of the operation can change their order, and this action will not alter the outcome.

Example 1:

$8*4=32$

Changing the order of the numbers in the operation:

$4*8=32\\\\Then,\\8*4=4*8$

Example 2:

$10*12=120$

Changing the order of the numbers in the operation:

$12*10=120\\\\Then,\\10*12=12*10$

4 0

3 years ago

Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean

earnstyle [38]

Answer:

$t=\frac{(1085 -1034)-(0)}{57.646\sqrt{\frac{1}{10}+\frac{1}{15}}}=2.167$

$p_v =2*P(t_{23}$

We see that the p value is lower than the significance level provided of 0.05 so then we have enough evidence to conclude that the true means are different at 5% of significance.

Step-by-step explanation:

Data given

$n_1 =10$ represent the sample size for group 1

$n_2 =15$ represent the sample size for group 2

$\bar X_1 =1085$ represent the sample mean for the group 1

$\bar X_2 =1034$ represent the sample mean for the group 2

$s_1=52$ represent the sample standard deviation for group 1

$s_2=61$ represent the sample standard deviation for group 2

We are assuming that the two samples are normally distributed with equal variances and that means:

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

System of hypothesis

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The degrees of freedom are given by:

$n_1+n_2 -2$

And the pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

Replacing we got:

$S^2_p =\frac{(10-1)(52)^2 +(15 -1)(61)^2}{10 +15 -2}=3323.043$

And the deviation would be:

$S_p=57.646$

The degrees of freedom are:

$df=10+15-2=23$

The statistic would be:

$t=\frac{(1085 -1034)-(0)}{57.646\sqrt{\frac{1}{10}+\frac{1}{15}}}=2.167$

The p value would be

$p_v =2*P(t_{23}$

We see that the p value is lower than the significance level provided of 0.05 so then we have enough evidence to conclude that the true means are different at 5% of significance.

6 0

3 years ago