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3 years ago

Having trouble with this problem

Mathematics

1 answer:

Artist 52 [7]3 years ago

7 0

Answer:

3,300 i THINK i used a calculator

Step-by-step explanation:

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Help with these, if theyre right, ill give brainliest

adelina 88 [10]

Answer:

q1: yes

q2: no

Step-by-step explanation:

2(5)+10(1)=20

10+10=20

20=20

(5)+(1)=6

5+1=6

6=6

(8)=(1)+3

8=1+3

8=4

3 0

3 years ago

Read 2 more answers

Draw the image of △ABC under the translation (x,y)→(x,y+3)

alexira [117]

Take the co-ordinates of your triangle and add three to the Y co-ordinates and keep the X co-ordinates the same. Then, graph. The shape should have slid upwards three points.

7 0

3 years ago

Solve: 5 + n > 2

tiny-mole [99]

$\\ \sf\longmapsto 5+n>2$

We have to find n
Take 5 to right side
sign will be changed

$\\ \sf\longmapsto n>2-5$

Simplify

$\\ \sf\longmapsto n>-3$

3 0

3 years ago

Can someone help me with this ASAP!!! And show the work plsss!

cupoosta [38]

Answer:

as soon as possible

Step-by-step explanation:

and it an 90 degree angle

u have to add it

5 0

3 years ago

Differentiate y=x⁴(1-2x⁵)⁶(5-8x³)².

Liula [17]

Step-by-step explanation:

Let $y(x)=f(x)g(x)h(x)$ where

$f(x) = x^4$

$g(x)= (1 -2x^5)^6$

$h(x)= (5 - 8x^3)^2$

so that

$y(x) = x^4(1 -2x^5)^6(5 - 8x^3)^2$

Recall that the derivative of the product of functions is

$y'(x)=f'(x)g(x)h(x)+f(x)g'(x)h(x)+f(x)g(x)h'(x)$

so taking the derivatives of the individual functions, we get

$f'(x) = 4x^3$

$g'(x) = 6(1 - 2x^5)^5(-10x^4)$

$h'(x) = 2(5 - 8x^3)(-24x^2)$

So the derivative of y(x) is given by

$y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2 + x^4 6(1 -2x^5)^5(-10x^4)(5 - 8x^3)^2 + x^4(1 -2x^5)^6 2(5 - 8x^3)(-24x^2)$

$y'(x) = 4x^3(1 -2x^5)^6(5 - 8x^3)^2$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 60x^8(1 -2x^5)^5(5 - 8x^3)^2$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:- 48x^6(1 -2x^5)^6 2(5 - 8x^3)$

3 0

3 years ago