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3 years ago

½(4k + 3r) ÷ 3^1 k = 9 r = 6 show work

Mathematics

2 answers:

suter [353]3 years ago

4 0

<h2><u>Question</u><u>:</u><u>-</u></h2>

½(4k + 3r) ÷ 3^1

k = 9

r = 6

show work

<h2><u>Solution</u><u>:</u><u>-</u></h2>

Given,

> k = 9

> r = 6

Applying the values,

=> 1/2 (4×9 + 3×6) ÷ 3¹

=> 1/2 (36 + 18) ÷ 3¹

=> 1/2 × 54 ÷ 3

=> 27 ÷ 3 (1/2 × 54 = 27)

=> 9

<h2><u>Answer</u><u>:</u><u>-</u><u> </u></h2>

9 (Nine)

vampirchik [111]3 years ago

3 0

Answer:

The solution is given below:

Step-by-step explanation:

$\\ \frac{1}{2} (4k + 3r) \div {3}^{1}$

As we know the value of k and r so the equation will be

$\\ \frac{1}{2} (4 \times 9 + 3 \times 6) \div {3}^{1}$

$\\ = \frac{1}{2} (36 + 18) \div 3$

$\\ = \frac{1}{2} \times 54 \div 3$

$\\ = \frac{1}{2} \times 18$

$\\ = 9$

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