We are asked to find ratio of two relative intensities. Let's start by rearranging formula for R:
For air-raid siren we have:
For jet engine noise we have:
To find out <span>many times greater is the relative intensity of the air-raid siren than that of the jet engine noise we need to divide these two numbers:
</span>tex] \frac{R_{1}}{R_{2}} = \frac{10^{15}}{10^{12}} =10^{3}=1000[/tex]
Answer:
1.7x3.9=6.63 so each shaded area is 6.63 then add
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
Answer:
y=x-1
Step-by-step explanation:
The equation is currently in standard form which is a+b=y and slope-intercept is y=mx+b where m is the slope and b is the y-intercept. To change the form we must move the terms around using Properties of Equality.
First, subtract 1 from both sides
x-y-1=1-1
x-y-1=0
Then, add y to both sides
x-y-1+y=0+y
x-1=y
So that is the equation in slope-intercept form with a slope of 1 and a y-intercept of -1.
From the coordinate plane, the podium that could be located relative to the center will be B. 288 feet west.
<h3>Coordinate plane</h3>
From the complete information, there is a park in Washington and the event planner plots the park on a coordinate plane.
The table contains points along the perimeter of the park. Since the event planner wants to put a podium at one of the foci, the point where the podium could be located relative to the center will be 288 feet west.
Learn more about coordinate plane on:
brainly.com/question/13854649
