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frez [133]
2 years ago
12

In an area of the Great Plains, records were kept on the relationship between the rainfall (in inches) and the yield of wheat (b

ushels per acre). Calculate the linear correlation coefficient. Round to three decimal places.
Rainfall (in inches), x 11.7 10 14.6 13.7 20 11.5 8.2 16.8 17.2
Yield (bushels per acre), y 54.5 50.2 62.8 63 86.4 53.2 35.9 80 82.8
Options:
A. 0.998
B. 0.900
C. 0.899
D. 0.981

Mathematics
1 answer:
vovikov84 [41]2 years ago
7 0

Answer: D. 0.981

Step-by-step explanation:

Step 1: For the given data table on x^2

We square all values given to us

Step 2: we repeat Same for Y^2 table too.

Step 3: XY table we multiply x and y

Step 4: we make a summation of them all

Step 5: we input our summer value into our formula.

Step 6 : we arrive at our answer which is 0.981

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Question
Jobisdone [24]

Answer:

The light bulb will reach the ground 1.25 seconds after it is dropped.

Step-by-step explanation:

We know that for an object that is in the air, the only force acting on it will be the gravitational force (where we are ignoring the air resistance)

Then the acceleration of the object is the gravitational acceleration, 32.17 ft/s^2

Then the acceleration of the light bulb is:

A(t) = (-32.17 ft/s^2)

Where the negative sign is because the acceleration is downwards.

Now, to get the velocity equation, we need to integrate the acceleration over time, we will get:

V(t) = (-32.17 ft/s^2)*t + V0

Where V0 is the initial velocity of the light bulb. Because it is dropped, the initial velocity will be zero, then V0 = 0m/s, then the velocity equation is:

V(t) =  (-32.17 ft/s^2)*t

Finally, to get the position equation we need to integrate again, we will get:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + P0

Where P0 is the initial height of the object, and in this case, we know that it is equal to 25 ft.

Then the position equation is:

P(t) = (1/2)*(-32.17 ft/s^2)*t^2 + 25ft

The object will hit the ground when P(t) = 0 ft, then we need to solve that equation for t:

P(t) =  (1/2)*(-32.17 ft/s^2)*t^2 + 25ft = 0 ft

          25 ft =  (1/2)*(32.17 ft/s^2)*t^2

         2*25ft = (32.17 ft/s^2)*t^2

           50ft =  (32.17 ft/s^2)*t^2

         √( 50ft/(32.17 ft/s^2)) = t = 1.25 s

The light bulb will reach the ground 1.25 seconds after it is dropped.

8 0
3 years ago
Estimate the sum of 8.43 + 8.12 + 7.98.
In-s [12.5K]

Answer:

we estimate it and get

the answer is 25.53

7 0
2 years ago
Whats equivalent<br> to 32/40
sattari [20]
16/20 is the correct answer
5 0
3 years ago
Read 2 more answers
What is the relationship between the digit 9 in 79,401
nikdorinn [45]
9,000 or (9×1,000) either one can be the answer
6 0
3 years ago
Q5 Q6.) Find the exact value of the six trigonometric functions of theta.
lilavasa [31]
5y - 2x + 1 = 0.
5y = 2x-1.

y = 2/5 x - 2/5

this tells us that tan(theta) = 2/5
sin(theta)/sqrt(1-sin^2(theta)) = 2/5
x/sqrt(1-x^2)=2/5
x^2/(1-x^2)=4/25
25x^2=4-4x^2
29x^2=4
x^2=4/29
x = -2/sqrt(29) because quadrant III
cos(x) = sqrt(1-4/29) = -5/sqrt(29)


tan(theta)=2/5
cos(theta)=-5/sqrt(29)
sin(theta)=-2/sqrt(29)
cot(theta)=5/2
sec(theta)=-sqrt(29)/5
csc(theta)=-sqrt(29)/2



5 0
3 years ago
Read 2 more answers
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