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Ksenya-84 [330]
3 years ago
14

Identify the slope and y-intercept of the line. y = 6x-5

Mathematics
1 answer:
Alexeev081 [22]3 years ago
3 0

Answer:

slope = 6

y-intercept = -5

Step-by-step explanation:

The equation is in slope-intercept form:

y = mx + b

where m is the slope and b is the y-intercept

Let's find the slope:

The slope is the number being multiplied by x.

y = mx + b

y = 6x - 5

Therefore, the slope is 6.

Let's find the y-intercept:

The y-intercept is the last number in the equation.

y = mx + b

y = 6x -5

Therefore, the y-intercept is -5.

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Zanzabum
\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)= \cfrac{1}{x}  \qquad 
\begin{cases}
x_1=2\\
x_2=b
\end{cases}\implies \cfrac{f(b)-f(2)}{b-2}=-\cfrac{1}{10}
\\\\\\
\cfrac{\frac{1}{b}-\frac{1}{2}}{b-2}=-\cfrac{1}{10}\implies 
\cfrac{\frac{2-b}{2b}}{b-2}=-\cfrac{1}{10}\implies \cfrac{2-b}{2b}=-\cfrac{b-2}{10}
\\\\\\


\bf \cfrac{2-b}{2b}=\cfrac{2-b}{10}\implies 20-10b=4b-2b^2\impliedby cross-multiplying
\\\\\\
2b^2-4b-10b+20=0\implies 2b^2-14b+20=0
\\\\\\
b^2-7b+10=0\implies 
(b-2)(b-5)=0\implies b=
\begin{cases}
\boxed{5}\\
2
\end{cases}
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