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mrs_skeptik [129]
3 years ago
14

Please help.....25 points!!!

Mathematics
2 answers:
ryzh [129]3 years ago
5 0

Answer:

Option 3

Step-by-step explanation:

y = ⅗x - 9

Make x the subject

⅗x = y + 9

x = 5y/3 + 15

Interswitch variables

g^-1(x) = 5x/3 + 15

kenny6666 [7]3 years ago
3 0

Answer:

C

Step-by-step explanation:

We want to find the inverse of g(x). One way to do this is to switch the g(x) and x in the original equation and then solve for g(x); that will give you the inverse.

Here, g(x)=\frac{3}{5} x-9. Switch the g(x) and x to become: x=\frac{3}{5} g(x)-9. Now solve for g(x) by isolating it:

x=\frac{3}{5} g(x)-9

x+9=\frac{3}{5} g(x)

\frac{5}{3} * (x+9)= g(x)

g(x)=\frac{5}{3} x+15

Thus, the answer is C.

Hope this helps!

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Find the constant of proportionality k. Then write an equation for the relationship between x and y
ExtremeBDS [4]

Question:

Find the constant of proportionality k. Then write an equation for the relationship between x and y

\begin{array}{ccccc}x & {2} & {4} & {6} & {8} \ \\ y & {10} & {20} & {30} & {40} \ \ \end{array}

Answer:

(a) k = 5

(b) y = 5x

Step-by-step explanation:

Given

\begin{array}{ccccc}x & {2} & {4} & {6} & {8} \ \\ y & {10} & {20} & {30} & {40} \ \ \end{array}

Solving (a): The constant of proportionality:

Pick any two corresponding x and y values

(x_1,y_1) = (2,10)

(x_2,y_2) = (6,30)

The constant of proportionality k is:

k = \frac{y_2 - y_1}{x_2 - x_1}

k = \frac{30-10}{6-2}

k = \frac{20}{4}

k = 5

Solving (b): The equation

In (a), we have:

(x_1,y_1) = (2,10)

k can also be expressed as:

k = \frac{y- y_1}{x- x_1}

Substitute values for x1, y1 and k

5 = \frac{y- 10}{x- 2}

Cross multiply:

y - 10 = 5(x - 2)

Open bracket

y - 10 = 5x - 10

Add 10 to both sides

y - 10 +10= 5x - 10+10

y = 5x

6 0
3 years ago
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                   = 7(h² - [6k]² )

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We know that:

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