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3 years ago

Which of these is another way to write the function f(x) = 5*

Mathematics

1 answer:

notka56 [123]3 years ago

5 0

Answer:

May you kindly provide us with a selection of choices? Thank you ! :)

Step-by-step explanation:

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HELPPPPPPP!!!!!! THIS IS DUE AT 4:20

vfiekz [6]

Answer:

B. PK = 15, RJ = 9

Step-by-step explanation:

RQ = 3

PQ = 5

✔️In ∆JKL, Q is the centroid. According to the centroid theorem, thus:

⅓(RJ) = RQ

⅓(RJ) = 3

Multiply both sides by 3

RJ = 3*3

RJ = 9

✔️Also, based on the centroid theorem,

⅓(PK) = PQ

⅓(PK) = 5

Multiply both sides by 3

PK = 5*3

PK = 15

3 0

3 years ago

The half life of a radioactive substance is 10 years. If 64 grams are placed in a

geniusboy [140]

Answer:

2 grams

Step-by-step explanation:

50 years is 5 half lives as 1 half life is 10 years.

64 divide 2 = 32-1 half life

32 divide 2 =16-2nd half life

16 divide 2 = 8-3rd half life

8 divide 2 = 4-4th half life

4 divide 2 = 2-5th half life

This means we will have 2 grams left of the radioactive substance after 50 years.

7 0

3 years ago

* giving brainliest * Find the measure of the arc. A 1469 E B MÁBC = [?]

Nata [24]

The answer is 1238... also you mad cute was good

8 0

3 years ago

LA= Round your answer to the nearest hundredth. A 2 5 B

Marina CMI [18]

Answer:

I'm not so clear with the question but I hope this helps

3 0

3 years ago

What is the volume of a pyramid whose base is a square of area 36 and whose four faces are equilateral triangles?

irina1246 [14]

Answer:

$V = 36\sqrt{2}$

Step-by-step explanation:

The volume of a pyramid is

$V = \dfrac{1}{3}Bh$

where B = area of the base, and h = height of the pyramid

The base is a square.

$A = s^2$

$s = \sqrt{A}$

$s = \sqrt{36}$

$s = 6$

The side of the base has length 6. Each face of the pyramid is an equilateral triangle with side of length 6.

An altitude of this triangle measures

$a = \sqrt{6^2 - 3^2}$

$a = \sqrt{27}$

The pyramid is formed by 4 equilateral triangles whose bases form a square. The tips of the faces meet at a single point on top. The vertical distance from that point to the center of the base is the height of the pyramid.

$h = \sqrt{(\sqrt{27})^2 - 3^2 }$

$h = \sqrt{27 - 9}$

$h = \sqrt{18}$

$h = 3 \sqrt{2}$

Volume of the pyramid:

$V = \dfrac{1}{3}Bh$

$V = \dfrac{1}{3}(36)(3\sqrt{2})$

$V = 36\sqrt{2}$

5 0

4 years ago