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3 years ago

10

Solve the two-step equation. -9x + 0.4 = 4 Which operation must be performed to move all the constants to the right side of the

equation? Then, which operation must be performed to isolate the variable? The solution to the equation is x = .

2 answers:

kykrilka [37]3 years ago

8 0

Answer:

x = -0.4

Step-by-step explanation:

We have the equation:

-9x + 0.4 = 4

First, the operation to move all the constants to the right side is subtraction since we would have to subtract 0.4 from each side, let's see this:

$-9x+0.4=4\\-9x+0.4-0.4=4-0.4\\-9x=3.6$

Now, we have all the constants on the right side of the equation.

Now, the operation we need to perform to isolate the variable is division (since the x has a -9 that is being multiplied by x) we need to do the opposite operation:

$-9x=3.6\\\frac{-9x}{-9} =\frac{3.6}{-9} \\x=-0.4$

<h3>Thus, the answer to this equation is x= -0.4</h3>

Elza [17]3 years ago

6 0

Answer: Which operation must be performed to move all the constants to the right side of the equation? Subtract 0.4

Then, which operation must be performed to isolate the variable? Divide by -9 on both sides

The solution to the equation is x =0.4

Step-by-step explanation:

I just did it on edgen

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3 years ago

What is the value of r in the equation -3(4r - 8)=-36

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Answer:

r=5

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

-3*(4*r-8)-(-36)=0

Step by step solution :

Step 1 :

Step 2 :

Pulling out like terms :

2.1 Pull out like factors :

4r - 8 = 4 • (r - 2)

Equation at the end of step 2 :

(0 - 12 • (r - 2)) - -36 = 0

Step 3 :

Step 4 :

Pulling out like terms :

4.1 Pull out like factors :

60 - 12r = -12 • (r - 5)

Equation at the end of step 4 :

-12 • (r - 5) = 0

Step 5 :

Equations which are never true :

5.1 Solve : -12 = 0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

5.2 Solve : r-5 = 0

Add 5 to both sides of the equation :

r = 5

One solution was found :

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7.Find the lengths of the missing sides in the triangle. If your answer is not an integer, leave it in simplest radical form. Th

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Here a right angled triangle given. one angle with measure $45^o$ given. The three sides of the triangle given 4, x, y.

We have to find, the sides which is opposite, adjacent and hypotenuse here.

We know that the side opposite to right angle is always hypotenuse. So, hypotenuyse = y.

The side adjacent to the given angle $45^o$ is x. So, here adjacent = x.

The opposite side is opposite to the given angle. So, opposite = 4.

Now we will use SOHCAHTOA that is $sin(x) =\frac{Opposite}{Hypotenuse} , cos(x) =\frac{Adjacent}{Hypotenuse} , tan(x) =\frac{Opposite}{Adjacent}$ , where x is the angle given.

To get x, we will use tan. So we will get,

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We know the value of $tan(45^o) = 1$ . By substituting the value we will get,

$1 =\frac{4}{x}$

To find x, we have to move x here to the left side by multiplying it to both sides. We will get,

$(1)(x) = (\frac{4}{x}) (x)$

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So we have got the value of x here.

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By substituting the value we will get,

$\frac{\sqrt{2}}{2} = \frac{4}{y}$

By cross multiplying we will get,

$(\sqrt{2}) (y) = (4)(2)$

$\sqrt{2}y = 8$

We will get y by dividing both sides by $\sqrt{2}$ , we will get,

$\frac{\sqrt{2}y}{\sqrt{2}} =\frac{8}{\sqrt{2} }$

$y =\frac{8}{\sqrt{2} }$

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$y =\frac{8\sqrt{2}}{(\sqrt{2})(\sqrt{2})}$

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