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svetlana [45]
3 years ago
8

PLEASE HELP thank you!!

Mathematics
1 answer:
iragen [17]3 years ago
8 0
Surface area:
5x4
5x8
5x8
4x5
4x5
4x5
4x8x2
4x4x2
Sum=256 in^2
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ANSWER FAST PLZ 65 POINTS!!!!!!!!!!!!!!!!!!
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Area of a circle is found using the formula: A = PI x r^2 where r is the radius of the circle, which is half the diameter.

Using the information in the problem you have:

A= PI x 15^2

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Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1

Lets solve the bottom most part first:

1-\frac{1}{1-sec^2x} \\\\

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1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}

now break the LCM

\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1

because 1/tan = cot x

and furthermore,

cot^2x+1\\cosec^2x

now we solve the above part and replace the bottom most part that we solved with cosec^2x

\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x

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