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3 years ago

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Juanita is cutting a piece of construction paper in the shape of a parallelogram. Two opposite sides of the parallelogram have l

engths (5n − 6) cm and (3n − 2) cm. The third side measures (2n + 3) cm. What are the lengths of two adjacent sides of the parallelogram? 2 cm and 2 cm 4 cm and 7 cm 7 cm and 9 cm 13 cm and 19 cm

1 answer:

Tamiku [17]3 years ago

6 0

Answer:

Second option: 4 cm and 7 cm.

Step-by-step explanation:

A Parallelogram is defined as a type of Quadrilateral, whose opposite sides are parallel and have equal lenght.

Since the opposite sides $(5n-6)cm$ and $(3n-2)cm$ have the same lenght, then:

$5n-6=3n-2$

Now you have to solve for "n":

Add 6 to both sides of the equation.

Subtract 3n to both sides of the equation:

$5n-6+(6)-(3n)=3n-2+(6)-(3n)\\5n-3n=-2+6\\2n=4$

Divide both sides of the equation by 2:

$\frac{2n}{2}=\frac{4}{2}\\\\n=2$

To know the lenght of two adjacent sides, susbtitute $n=2$ into the third side $(2n + 3)cm$ and into one of the the sides that are opposite to eache other. Then:

$(2(2)+3)cm=7cm\\\\(5(2)-6)cm=4cm$

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A couple intends to have two children, and suppose that approximately 52% of births are male and 48% are female.

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a) Probability of both being males is 27%

b) Probability of both being females is 23%

c) Probability of having exactly one male and one female is 50%

Step-by-step explanation:

a)

The probability that the birth is a male can be written as

$p(m) = 0.52$ (which corresponds to 52%)

While the probability that the birth is a female can be written as

$p(f) = 0.48$ (which corresponds to 48%)

Here we want to calculate the probability that over 2 births, both are male. Since the two births are two independent events (the probability of the 2nd to be a male does not depend on the fact that the 1st one is a male), then the probability of both being males is given by the product of the individual probabilities:

$p(mm)=p(m)\cdot p(m)$

And substituting, we find

$p(mm)=0.52\cdot 0.52 = 0.27$

So, 27%.

b)

In this case, we want to find the probability that both children are female, so the probability

$p(ff)$

As in the previous case, the probability of the 2nd child to be a female is independent from whether the 1st one is a male or a female: therefore, we can apply the rule for independent events, and this means that the probability that both children are females is the product of the individual probability of a child being a female:

$p(ff)=p(f)\cdot p(f)$

And substituting

$p(f)=0.48$

We find:

$p(ff)=0.48\cdot 0.48=0.23$

Which means 23%.

c)

In this case, we want to find the probability they have exactly one male and exactly one female child. This is given by the sum of two probabilities:

- The probability that 1st child is a male and 2nd child is a female, namely $p(mf)$

- The probability that 1st child is a female and 2nd child is a male, namely $p(fm)$

So, this probability is

$p(mf Ufm)=p(mf)+p(fm)$

We have:

$p(mf)=p(m)\cdot p(f)=0.52\cdot 0.48=0.25$

$p(fm)=p(f)\cdot p(m)=0.48\cdot 0.52=0.25$

Therefore, this probability is

$p(mfUfm)=0.25+0.25=0.50$

So, 50%.

Learn more about probabilities:

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Anthony decided to buy two DVDs that were not included in the deal. His price after tax was $21.60. What was the cost of the two

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Please help another assignment I’m not very good at math !!

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Answer:

Prime Factorization of 576

$576=2\times 2\times 2\times 2\times 2\times 2\times 3\times 3$

Prime Factorization of 64

$64=2\times 2\times 2\times 2\times 2\times 2$

The Expression in simplest form is

$\sqrt{\dfrac{576}{64} }=\dfrac{3}{1}$

Step-by-step explanation:

Simplify:

$\sqrt{\dfrac{576}{64} }$

Now,

Prime Factorization of 576

$576=2\times 288\\576=2\times 2\times 144\\576=2\times 2\times 2\times 72\\576=2\times 2\times 2\times 2\times 36\\576=2\times 2\times 2\times 2\times 2\times 18\\576=2\times 2\times 2\times 2\times 2\times 2\times 9\\576=2\times 2\times 2\times 2\times 2\times 2\times 3\times 3$

Prime Factorization of 64

$64=2\times 32\\64=2\times 2\times 16\\64=2\times 2\times 2\times 8\\64=2\times 2\times 2\times 2\times 4\\64=2\times 2\times 2\times 2\times 2\times 2$

Now,

$\sqrt{\dfrac{576}{64} }=\sqrt{\dfrac{2\times 2\times 2\times 2\times 2\times 2\times 3\times 3}{2\times 2\times 2\times 2\times 2\times 2} }\\ \sqrt{\dfrac{576}{64} }=\sqrt{\dfrac{3\times 3}{1}}\\\therefore \sqrt{\dfrac{576}{64} }=3$

The Expression in simplest form is

$\sqrt{\dfrac{576}{64} }=\dfrac{3}{1}$

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3 years ago