Ask question

Ask question

All categories

3 years ago

5

An arts academy requires there to be 4 teachers for every 100 students and 3 tutors for every 30 students. How many students doe

s the academy have per teacher? Per tutor? How many Tito’s does the academy need if it has 110 students?

1 answer:

jekas [21]3 years ago

6 0

Answer:

18 students for each teacher and 10 for each tutor, and if the academy had 80 students it would have 8 tutors

Step-by-step explanation:

You might be interested in

4y square + y - 45 when y=-5

kobusy [5.1K]

Given:

The expression is

$4y^2+y-45$

To find:

The value of the given expression when y=-5.

Solution:

We have,

$4y^2+y-45$

Putting y=-5, we get

$4(-5)^2+(-5)-45$

$=4(25)-5-45$

$=100-50$

$=50$

Therefore, the value of the given expression is 50 when y=-5.

7 0

3 years ago

A rectangle with the vertices (3, -2), (3, -4), (7, -2), (7, -4) is reflected across the x-axis and the rotated 90 degrees count

irga5000 [103]

Answer:

The new vertices are: $(-2,3),(-4,3),(-2,7),(-4,7)$

Step-by-step explanation:

The given vertices are $(3,-2),(3,-4),(7,-2),(7,-4)$

Rule for reflection about x axis is $(x,y)$ → $(x,-y)$ .

So, $(3,-2)$ → $(3,2)$

$(3,-4)$ → $(3,4)$

$(7,-2)$ → $(7,2)$

$(7,-4)$ → $(7,4)$

Now, new vertices after reflection about x axis are $(3,2),(3,4),(7,2),(7,4)$ .

Rule for 90 degree rotation counter-clockwise is $(x,y)$ → $(-y,x)$ .

So, $(3,2)$ → $(-2,3)$

$(3,4)$ → $(-4,3)$

$(7,2)$ → $(-2,7)$

$(7,4)$ → $(-4,7)$

Therefore, the new rectangle after reflection about x axis and rotated 90 degrees counter-clockwise has the following vertices:

$(-2,3),(-4,3),(-2,7),(-4,7)$

4 0

3 years ago

What is this shape, and what’s the name in two different ways? 20 points!!

Schach [20]

Answer:

Triangular Prism.

Two other ways are parallelopiped and quadrangular prism

Step-by-step explanation:

Here are more ways you can name it:

parallelopiped, triangular prism, parallelepiped,quadrangular prism, parallelopipedon, polyhedron, parallelepipedon.

Hope it helps!

3 0

3 years ago

Read 2 more answers

M&M plain candies come in various colors. According to the M&M/Mars Department of Consumer Affairs, the distribution of

lyudmila [28]

Answer:

A) 0.12. Yes. Choosing a green and blue M&M is possible

B) 0.43. Yes. Choosing a yellow and red M&M is possible

C) 0.78

Step-by-step explanation:

First of all, the summation of the distribution of all colours is;

Σ(all colors ) = 22% + 20% + 23% + 10% + 6% + 6% + 13% = 100%, or 1.

Thus;

a) P(green candy or blue candy) is;

P(GREEN ∪ BLUE) = P(G) + P(BL)

P(GREEN ∪ BLUE) = 6%+6%

P(GREEN ∪ BLUE) = 12% or 0.12

Now, due to the fact that we have to choose ONE candy and only ONE candy at random, then they are mutually exclusive: Yes. Choosing a green and blue M&M is possible

b)P(yellow candy or red candy is;

P(YELLOW ∪ RED) = P(Y) + P(R)

P(YELLOW ∪ RED) = 20% + 23% = 43% or 0.43

Yes. Choosing a yellow and red M&M is possible

c) P(NOT PURPLE)

the probability of having a purple is;

P(PURPLE) = 22% or 0.22

So, the Probability of NOT having a PURPLE is 1 - 0.22 = 0.78

4 0

3 years ago

I GIVEEE BRAINLILSTTT

ludmilkaskok [199]

Answer:h5h5h5h

rfwetgerg5g

Step-by-step explanation:5h5h5h5

5h5h5h5hr5h5eh5h5h5h7,lio.iu.i

5 0

3 years ago