The amount invested in the account that yields 7% interest is $4000.
The amount invested in the account that yields 12% interest is $1000.
<h3>What are the linear equations that represent the question?</h3>
a + b = 5000 equation 1
0.07a + 0.12b = 400 equation 2
Where:
a = amount invested in the account that yields 7% interest.
b = amount invested in the account that yields 12% interest.
<h3>How much is invested at each rate?</h3>
Multiply equation 1 by 0.07
0.07a + 0.07b = 350 equation 3
Subtract equation 3 from equation 2
0.05b = 50
b = 50 / 0.05
b = 1000
Subtract 1000 from 5000: 5000 - 1000 = 4000
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You have to get rid of 1/2 by multiplying it by its recriprocal which is like this:
1) 1/2 x 2/1 which equals to zero and you do the same to the other side.
2) -12 x 2/1 = -24x then multiply-24x with 7 which equals -168.
16-x= -24x -168
3) subtract 16 to the other side and subtract 24x with x
23x= -184
4) divide by 23 to isolate x and you get -8
5) x=-8
Step-by-step explanation:
3^2
18^2 in scientific notation
