1.
The equation for this problem would be
y = (?)x + 190
With y being the height after a given amount of years and x being the amount of years passing. We would need to find ?, the rate of how fast the tree grows. The problem gives us y = 274 centimeters and x = 3 years
Let’s plug in and solve for ?
274 = ?(3) + 190
84 = ?3
28 = ?
The tree grew 28 cm per year
2.
Since we know the rate of change and y, let’s just plug in values
344 = 28x + 190
154 = 28x
5.5 = x
5.5 years since Renata moved.
Answer:
We calculate for the dimensions (the length of the sides) of both the poster and the cube. If the length of the side of the poster is shorter compared to that of the box then, the poster will lie flat in the cube. However, if the poster has a length that is longer than that of the cube then, it will not lie flat in the cube.
length of the poster = sqrt (9 ft^2) = 3 ft
length of the cube = cbrt (30 ft^3) = 3.11 ft
Since, the length of the cube is longer compared to the length of the poster then, the poster will lie flat on the cube
Answer:
False
Step-by-step explanation:
Like terms have the same variable and are raised to the same exponent, and 6x has a variable of x while 6 has none at all, so they are not like terms.
Answer:
2x + 4
Step-by-step explanation:
So sorry if this is wrong, I'm rusty in this area of math
Answer:
The cost of one adult ticket is $13, and the price of one student ticket is $4.
Step-by-step explanation:
This question can be solved using a system of equations.
I am going to say that:
x is the cost of an adult ticket
y is the cost of a student ticket.
6 adult tickets and 1 student ticket for a total of $82
This means that
The school took in $51 on the second day by selling 3 adult tickets and 3 student tickets.
This means that
Simplifying by 3
Since
The cost of one adult ticket is $13, and the price of one student ticket is $4.
