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RSB [31]
3 years ago
10

2. Is -1/3-4/5 positive,negative, or zero ?

Mathematics
1 answer:
Ivan3 years ago
7 0
Negative because if you take away from a negative, your just making it smaller... hope this helps!
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QUICK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! The ratio of the hours the Teenage Mutant Ninja Turtles spend training,
kicyunya [14]

Answer:

6 hours

The difference between the ratio numbers is 8-3 = 5. That corresponds to the 10-hour difference between training hours and pizza-eating hours. Thus, each ratio unit stands for 2 hours. The 3 ratio units spent eating pizza stand for ...

3×2 hours = 6 hours eating pizza

Step-by-step explanation:Hopefully this helped, if not HMU and I will get u a better answer!

and get i get brainliest plz, im trying to upgrade my statis

3 0
3 years ago
Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin
saw5 [17]
Treat \mathcal C as the boundary of the region \mathcal S, where \mathcal S is the part of the surface z=2xy bounded by \mathcal C. We write

\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r

with \mathbf f=(y+7\sin x,z^2+9\cos y,x^3).

By Stoke's theorem, the line integral is equivalent to the surface integral over \mathcal S of the curl of \mathbf f. We have


\nabla\times\mathbf f=(-2z,-3x^2,-1)

so the line integral is equivalent to

\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S
=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv


where \mathbf s(u,v) is a vector-valued function that parameterizes \mathcal S. In this case, we can take

\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)

with 0\le u\le1 and 0\le v\le2\pi. Then

\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv

and the integral becomes

\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv
=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi<span />
4 0
3 years ago
Courtney had $55 to spend at the fair. She paid $22.50 for rides and $14.25 for lunch and snacks. Courtney says she has $18.25 l
Sever21 [200]
B. is the answer all it asking you is she correct that she only has 18.25 to play with for the games.


3 0
3 years ago
Y
mina [271]

Answer:

y inversely proportional to 1/x

y=4, x=16

4=k/16

k=64

find y when x=8

y=64/8

y=8

3 0
3 years ago
Plzzzz help Lia brought 21 shirts and plants. Her total was $357. Pants cost $25 each, and shirts cost $14.50 each. How many of
OverLord2011 [107]

Answer:

she brought 21 shirts and 2 pants

Step-by-step explanation:

shirts

21× 14.50 = 304.5

357- 304.5 = 52.5

pants

52.5 ÷ 25 = 2.1

5 0
3 years ago
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