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3 years ago

8

What is the radius of the circle that has an area of

*pi" alt="81*x*pi" align="absmiddle" class="latex-formula"> degrees

1 answer:

crimeas [40]3 years ago

7 0

Answer:

R=9

Step-by-step explanation:

the formula for area of a circle is pi r squared

where r denotes the radius of the circle

equating the formula for area with the area of the circle provided

p\i r squared = 81 p\i

r squared = 81

r = radical 81

r =9 inches

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-2x+10
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Answer:

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Which expression is a difference of cubes? 9w^33-y^12 18p^15-q^21 36a^22-b^16 64c^15- a^26

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we know that

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Let's verify each case to determine the solution to the problem

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we know that

$9=3^{2}$ ------> <u>the term is not a perfect cube</u>

$w^{33}=(w^{11})^{3}$ ------> the term is a perfect cube

$y^{12}=(y^{4})^{3}$ ------> the term is a perfect cube

therefore

The expression $9w^{33} -y^{12}$ is not a difference of cubes because the term $9$ is not a perfect cube

<u>case B)</u> $18p^{15} -q^{21}$

we know that

$18=2*3^{2}$ ------> <u>the term is not a perfect cube</u>

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$q^{21}=(q^{7})^{3}$ ------> the term is a perfect cube

therefore

The expression $18p^{15} -q^{21}$ is not a difference of cubes because the term $18$ is not a perfect cube

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we know that

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$b^{16}$ ------> <u>the term is not a perfect cube</u>

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we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

$c^{15}=(c^{5})^{3}$ ------> the term is a perfect cube

$a^{26}$ ------> <u>the term is not a perfect cube</u>

therefore

The expression $64c^{15} -a^{26}$ is not a difference of cubes because the term $a^{26}$ is not a perfect cube

I'm adding a new case so I can better explain the problem

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we know that

$64=2^{6}=(2^{2})^{3}$ ------> the term is a perfect cube

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$d^{27}=(d^{9})^{3}$ ------> the term is a perfect cube

Substitute

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Answer:

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Step-by-step explanation:

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1% = 7 ÷ 22

100% = (7÷22) * 100

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