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algol [13]
3 years ago
8

B) David and Andrew are traveling to a Mathematics conference. David travels 110 miles in the same time that Andrew travels 140

miles. Andrew travels 15 miles per hour faster than David. Find the average rate of each person.
Mathematics
1 answer:
nasty-shy [4]3 years ago
3 0

Answer:

David's average speed is 55 mph and Andrew's average speed is 70 mph

Step-by-step explanation:

Let David's speed be s.

Average speed is given as:

speed = distance / time

They both spent the same time, t.

David's speed is:

s = 110 / t

=> t = 110 / s

Andrew travels 15 mph faster than David.

Andrew's speed is:

(15 + s) = 140 / t

=> t = 140 / (15 + s)

Therefore, since they spent the same time:

110 / s = 140 / (15 + s)

Cross multiply:

110(15 + s) = 140s

1650 + 110s = 140s

1650 = 140s - 110s

30s = 1650

s = 1650 / 30

s = 55 mph

Andrew's speed is:

15 + 55 = 70 mph

Therefore, David's average speed is 55 mph and Andrew's average speed is 70 mph.

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Find the value of x when : 2^30/8^9=2^x
artcher [175]

Answer:

x = -3

Step-by-step explanation:

Okay, the first thing to do is get that 8 away from the fraction. How can we do it? When you have 2³ you have 8, is the same thing, so let's do it:

2³⁰/(2³)⁹ = 2^x

When you have a number with the shape (a^x)^y, you can write it as a^(x•y), so:

(2³)⁹ = 2^3•9 = 2²⁷

Now we have:

2³⁰/2²⁷ = 2^x

When you have a division like this: (a^x)/(a^y), you can write it as a^(x-y), so:

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Now you know that x = -3

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3 years ago
Which is the best strategy to solve this problem?
FinnZ [79.3K]
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8 0
3 years ago
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What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)? y = - 2y = -3x + 7 2x + 3y -
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