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pav-90 [236]
1 year ago
12

Helpppppp show your work

Mathematics
2 answers:
PIT_PIT [208]1 year ago
7 0
The correct answer would be-5/3
Tpy6a [65]1 year ago
6 0

Answer:

-5/3

Step-by-step explanation:

Do PEMDAS

8 - 11 = -3

-3 ^ 3 = -27

-(-27) = 27

I-14I = 14

3 x 14 = 42

27 - 42 = -15

2^4 = 16

16 - 7 = 9

-15/9 = -5/3

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Explain me how to do it plssss I need help
pashok25 [27]
2 divided by 47 so d....
Because they say fraction of this listed species are endangered plants
So you use total amount of endangered plant,2....and divide it by the total amount in the whole list 47
5 0
3 years ago
A circle is inscribed in a square with a side length of 144. If a point in the square is chosen at random, what is the probabili
____ [38]

Given :

A circle is inscribed in a square with a side length of 144.

So, radius of circle, r = 144/2 = 72 units.

To Find :

The probability that the point is inside the circle.

Solution :

Area of circle,

A_c = \pi r^2\\\\A_c = 3.14 \times 72^2\ units^2\\\\A_c = 16277.76 \ units^2

Area of square,

A_s = (2r)^2\\\\A_s = ( 2 \times 72)^2\ units^2\\\\A_s = 20736\ units^2

Now, probability is given by :

P = \dfrac{A_c}{A_s}\\\\P = \dfrac{16277.76}{20736}\\\\P = 0.785

Therefore, the probability that the point is inside the circle is 0.785 .

4 0
3 years ago
The base of a solid is the region in the first quadrant between the graph of y=x2 and the x -axis for 0≤x≤1 . For the solid, eac
nata0808 [166]

Answer:

The volume of the solid is π/40 cubic units.

Step-by-step explanation:

Please refer to the graph below.

Recall that the area of a semi-circle is given by:

\displaystyle A=\frac{1}{2}\pi r^2

The volume of the solid will be the integral from <em>x</em> = 0 to <em>x</em> = 1 of area A. Since the diameter is given by <em>y</em>, then the radius is <em>y/2</em>. Hence, the volume of the solid is:

\displaystyle V=\int_0^1\frac{1}{2}\pi \left(\frac{y}{2}\right)^2\, dx

Substitute:

\displaystyle V=\frac{1}{2}\pi\int_0^1\left(\frac{x^2}{2}\right)^2\, dx

Simplify:

\displaystyle V=\frac{1}{2}\pi \int_0^1\frac{x^4}{4}\, dx

Integrate:

\displaystyle V=\frac{1}{2}\pi \left[\frac{x^5}{20}\Big|_0^1\right]

Evaluate:

\displaystyle V=\frac{\pi}{40}\left((1)^5-\left(0\right)^5\right)=\frac{\pi}{40}\text{ units}^3

The volume of the solid is π/40 cubic units.

4 0
3 years ago
Omg why is math a pain in the rear-end
Paladinen [302]
Rightttt! I hate it but I have no idea haha
7 0
3 years ago
Suppose cos(O) = 12/13, Quadrant I. Find sin(O).<br> A:13/12<br> B:5/13<br> C:13/5<br> D:5/12
noname [10]

Answer:

B: 5/13

Step-by-step explanation:

pythagoras theorem: a^2 + b^2 (sides) = c^2 (hypotenuse)

a^2 + 12^2 = 13^2

a^2 + 144 = 169

a^2 = 25

a = 5

sin = opp/hyp

sin 5/13

Hope this helps

7 0
3 years ago
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