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3 years ago

What is the linear equation for this graph? (y=mx+b)

Mathematics

2 answers:

mart [117]3 years ago

4 0

Answer:

y = -3x - 3

Step-by-step explanation:

the y-intercept is -3 as shown in the graph, so, b = -3

if you count, the rise is 3 and the run is -1, so the slope will be -3/1

-3/1 equals to -3

y = -3x - 3

denis23 [38]3 years ago

4 0

Answer:

y = –3x – 3

Step-by-step explanation:

m = the slope which is 3/1, or 3. Since the line is going from the bottom right corner to the top left, it is a negative slope so –3.

b = the y-intercept which is –3.

So,

y = –3x – 3

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Answer:

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Step-by-step explanation:

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4 years ago

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Over [174]

Answer:

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3 years ago

The x-values below are hours spent studying, and the y-values are grades on a test. What is the Pearson product-moment correlati

steposvetlana [31]

Answer:

The Pearson product-moment correlation coefficient is $r = 0.9556$

Step-by-step explanation:

The Pearson product-moment correlation coefficient (PMCC) is a numerical value between -1 and 1 that expresses the strength of the linear relationship between two variables.When r is closer to 1 it indicates a strong positive relationship. A value of 0 indicates that there is no relationship. Values close to -1 signal a strong negative relationship between the two variables.

To find the PMCC of the following data, you must:

$\begin{array}{c|ccccc}X&3.2&3&1&2.5&1.9\\Y&90&88&57&86&79\end{array}$

Step 1: Find $X\cdot Y$ , $X\cdot X$ and $Y\cdot Y$ as it was done in the table below.

Step 2: Find the sum of every column to get

$\sum{X}=11.6 ~,~ \sum{Y}=400 ~,~ \sum{X \cdot Y}=974.1 ~,~ \sum{X^2}=30.1 ~,~ \sum{Y^2}=32730$

Step 3: Use the following formula to find the PMCC.

$\begin{aligned}r~&=~\frac{n\cdot\sum{XY} - \sum{X}\cdot\sum{Y}} {\sqrt{\left[n \sum{X^2}-\left(\sum{X}\right)^2\right] \cdot \left[n \sum{Y^2}-\left(\sum{Y}\right)^2\right]}} \\r~&=~\frac{ 5 \cdot 974.1 - 11.6 \cdot 400 } {\sqrt{\left[ 5 \cdot 30.1 - 11.6^2 \right] \cdot \left[ 5 \cdot 32730 - 400^2 \right] }} \approx 0.9556\end{aligned}$