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svp [43]
3 years ago
11

For the graph, locate the x-intercept and y-intercept.

Mathematics
1 answer:
alexgriva [62]3 years ago
5 0
X-intercept = -4
y-intercept = -8
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A cone is cut into a cube as shown below. If the cone has a diameter of
Butoxors [25]

Answer:

184.43in².

Step-by-step explanation:

Total surface area of the solid = volume of the cube - the volume of the cone

For the CUBE;

Volume of the cube = L³ where L is the length of one side of the cube.

Since a cone of diameter of 6in is cut into a cube, then the length of the cube will be 6in.

Volume of the cube = 6³ = 216in³

For the CONE;

Volume of the cone = 1/3 πr²h

r is the radius of the cone = diameter/2

r = 6/2 = 3in

slant height l = 4.5in

the height h of the cone will be derived using the Pythagoras theorem.

l² = h²+r²

4.5² = h²+3²

h² = 4.5²-3²

h² = 11.25

h=√11.25

h = 3.35in

Volume of the cone = 1/3 × π × 3²× 3.35

= 31.57in³

Total surface area of the solid = 216in³-31.57in³

= 184.43in²

3 0
3 years ago
How do the signs of the coordinates relate
aliina [53]

Answer:

If a point has these signs of coordinates: +,− then the point lies in the quadrant 4. If it is like 0,+, the point lies on the positive y axis. If it is like 0,−, the point lies on the negative y axis. If it is like +,0, the point lies on the positive x axis.

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A 250-gal tank is initially filled with brine (salt-water mixture) containing 100 lb of salt. Brine containing 3 lb of salt per
gulaghasi [49]

Answer:

x(t) = 581.66 lb

Step-by-step explanation:

From the given information:

Consider the salt quantity in the tank at time t be x(t) lb.

∴ the rate of change of salt content in the tank is \dfrac{dx}{dt}= Rate \ of \  \ inflow - rate \ of \  \ outflow

where:

the rate of inflow = salt conc. × flow rate = 3 lb/gallon × 7 gallons

=21 lb/s

rate of outflow = salt conc. in the tank  × flow rate

= x/250 ×  9

= 9x/250  lb/s

∴

\dfrac{dx}{dt} = 21 - \dfrac{9x}{250}

\dfrac{dx}{dt} + \dfrac{9x}{250}= 21

This is a 1st order linear differentiation,

The integrating factor if e^{^{ \int \dfrac{9}{250}\ dt}} = e^{^{ \dfrac{9t}{250} }}

∴

e^{^{ \dfrac{9t }{250}}} \ \ x(t) = \int 21 e^{\dfrac{9t}{250}} \ dt + C

e^{^{ \dfrac{9t }{250}}} \ \ x(t) =  21 \times \dfrac{250}{9}e^{\dfrac{9t}{250}} + C

x(t) = \dfrac{1750}{3}+Ce^{^{\dfrac{-9t}{250}}}     at  t = (0) and x(0) = 100 lb

Hence;

100 = \dfrac{1750}{3}+C

C = \dfrac{1750}{3} -100

C = - \dfrac{1450}{3}

∴x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-9t}{250}}}

after time t = 1 minute i.e 60 s

x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-9 \times 60}{250}}}

x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-540}{250}}}

x(t) = 581.66 lb

5 0
3 years ago
Can someone help me with it? click on the photo to see it in full screen
dsp73

Answer:

Angie will need to save $2.50 for 8 more weeks to get $50

Step-by-step explanation:

Angie has already saved $30

12(2.5)=30

So since she needs $20 more you divide 20 by 2.5 and you get your answer.

20/2.5=8 weeks

6 0
3 years ago
Geometry - Similar
oee [108]

Answer:

the length of AB=5cm

I hope this help you

5 0
2 years ago
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