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puteri [66]
3 years ago
10

Find the value of x in the isosceles triangle shown​

Mathematics
2 answers:
hichkok12 [17]3 years ago
5 0

Answer:

Option 4

Step-by-step explanation:

sqrt(3² + 2²)

sqrt(9+4)

sqrt(13)

Norma-Jean [14]3 years ago
3 0

Answer:

x = \sqrt{13}

Step-by-step explanation:

The line from the vertex to the base is a perpendicular bisector and divides the triangle into 2 right triangles.

Consider the right triangle on the left with base 2

Using Pythagoras' identity

The square on the hypotenuse (x) is equal to the sum of the squares on the other 2 sides, that is

x² = 2² + 3² = 4 + 9 = 13 ( take the square root of both sides )

x = \sqrt{13}

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