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natita [175]
3 years ago
15

4.

Mathematics
1 answer:
denis23 [38]3 years ago
6 0
The answer is none. There are no solutions
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Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either likes o
spayn [35]

Answer: There are 32 students who like brussels sprouts but dislike beans.

Step-by-step explanation:

Since we have given that

Number of students eat in the cafeteria = 120

Fraction dislike lime beans = \dfrac{2}{3}

Fraction who dislike lime beans and brussles sprouts both = \dfrac{2}{3}\times \dfrac{3}{5}

Fraction who dislikes lime beans but not brussles is given by

\dfrac{2}{3}(1-\dfrac{3}{5})\\\\=\dfrac{2}{3}\times \dfrac{2}{5}\\\\=\dfrac{4}{15}

So, Number of students who like brussels sprouts but dislike lima beans is given by

\dfrac{4}{15}\times 120\\\\=32

Hence, there are 32 students who like brussels sprouts but dislike beans.

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3 years ago
What was the first public statement in support of the creation of a Jewish state?
Ira Lisetskai [31]
The answer is D the Balfour Declaration
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3 years ago
A pie can be cut into more than seven pieces by making four diameter cuts.
n200080 [17]
I'm pretty sure it's true
7 0
3 years ago
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The sum of 5 times a larger number and twice a smaller is 5. The difference of 4 times the larger and the smaller number is 4. F
Gemiola [76]

Answer:

1 and 0

Step-by-step explanation:

Let's call the smaller number x and the larger number y.

This means 5y+2x=5.

Also, 4y-x=4.

This is a system of equations. There are two main ways two solve this.

Method 1: Substitution

5y+2x=5

4y-x=4

Solve for one of the variables, then substitute it back into one of the equations to solve for the other variable.

I will take 4y-x=4 and solve for x.

4y=4+x

x=4y-4

Then substitute for x in the other equation and solve for y.

5y+2x=5

5y+2(4y-4)=5

5y+8y-8=5

13y=13

y=1

Now we can go back to our equation for x and substitute for y.

x=4y-4

x=4(1)-4=0

y, the larger number, is 1 and

x, the smaller number, is 0

Method 2: Elimination

5y+2x=5

4y-x=4

Change the equations so that the coefficient of one of the variables in an equation is opposite the one in the other equation. Then add the equations and solve for each variable.

If I multiply both sides of the second equation, 4y-x=4, by 2, the coefficient of x will become -2. In the first equation, the coefficient is 2, so they will become opposites.

4y-x=4

becomes

8y-2x=8

Now we have 5y+2x=5 and 8y-2x=8.

Add the sides of both equations to cancel the x values.

5y+2x+8y-2x=5+8

13y=13

y=1

like last time, we can substitute for y in any of the original equations to get x.

5y+2x=5

5(1)+2x=5

5+2x=5

2x=0

x=0

y, the larger number, is 1 and

x, the smaller number, is 0

6 0
3 years ago
HELP PLEASE NEED THIS DONE
givi [52]

Answer:

Step-by-step explanation:

A

4 0
3 years ago
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