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-BARSIC- [3]
3 years ago
15

Please answer these questions!!!!!! Fast!!!!!!

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0

Answer:

For an object of mass M and velocity V, the kinetic energy is written as:

K = (M/2)*V^2

And also remember that:

1 J = 1 kg*m/s

a) we know that:

Mass = M = 0.7 kg

Velocity = V = 60 m/s

Then the kinetic energy is:

K = (0.7kg/2)*(60m/s)^2 = 1,260 J

b) We know that in a closed system, the energy is conserved.

This means that if we hit an object with an energy E, the maximum energy that we can give to that object is E.

Then if we have a bat of mass M = 2kg, and velocity V = 30m/s

The kinetic energy of the bat (before hitting the ball) is:

K = (2kg/2)*(30m/s)^2 = 900 J

Obviously, this will never happen, because after we hit the ball the bat keeps moving for a bit, meaning that it still has some kinetic energy and it did not transfer all of the kinetic energy to the ball. But we can not have a more precise estimation, because we do not know the mass of the ball and a lot of other needed information, so we can conclude that, the theoretical maximum energy that could be given to the ball, is 900 J.

c) Here we have:

Mass = M = 1950 kg

Velocity = V = 10 m/s

then the energy is:

K = (1950kg/2)*(10 m/s)^2 = 97,500 J.

d) Notice that in the equation of the kinetic energy we have the velocity squared, which means that the contribution of the velocity is larger than the contribution of the mass.

Then the option with the largest velocity most likely would have the largest kinetic energy, then the correct option is the second counting from the top, with a kinetic energy equal to:

K = (0.25 kg/2)*(50m/s)^2 = 312.5 J.

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Solnce55 [7]
The recipricol of -2/9 is 9/2, or  4 1/2


remember to change the sign (forgot to myself)

hope this helps
7 0
3 years ago
Read 2 more answers
Find the mode of this data set:<br> 31, 30, 32, 31, 30, 31, 32,<br> 33, 30, 31, 31, 30, 32
MariettaO [177]

Answer:

31 is the mode of the data as it appears 5 times

4 0
2 years ago
Write a quadratic function to model the vertical motion for each​ situation, given ​h(t) equals negative 16t squared plus v0t+h0
Mashcka [7]

Answer:

hmax = 194 ft

The maximum height is 194 ft

Step-by-step explanation:

According to the given equation for the model of the vertical motion. The height at any point in time can be written as;

h(t) = -16t^2 + v0t + h0 .......1

Where;

h(t) = height at time t

t = time

v0 = initial velocity = 96 ft/s

h0 = initial height = 50 ft

To determine the maximum height we need to differentiate the equation 1 to find the time at which it reaches maximum height;

At the highest point/height h' = dh/dt = 0

h'(t) = -32t +v0 = 0

-32t + v0 = 0

t = v0/32

t = 96/32

t = 3 s

At t=3 it is at maximum height.

The maximum height can be derived from equation 1;

Substituting the values of t,v0,h0 into equation 1;

h(t) = -16t^2 + v0t + h0 .......1

hmax = -16(3)^2 + 96(3) + 50 = 194 ft

hmax = 194 ft

The maximum height is 194 ft

5 0
3 years ago
Wich algebraic expression represents ”forty times a number”?<br><br> 40+n<br> 40n<br> n-40<br> 40/n
Reika [66]
The answer to the problem is 40n
4 0
3 years ago
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Find all real zeros of t<br>f(x)=x-14x² + 47x-18​
BabaBlast [244]

Answer:

x=3/7 and x= 3

Step-by-step explanation:

First simplify:

-14 x^2 +48x -18

divide everything by -2

-2(7 x^2 -24x +9) (Multiply the leading coefficient 7 by the constant 9)

-2 (x^2 -24x +63)

-2 [(x-3)(x-21)] Now divide the 7 that you multiplied earlier from 3 and 21

-2 [(x-3/7)(x-21/7)]

-2 [(7x-3)(x-3)]

Hence, the zeroes are 3/7 and 3

Hope this helps!

If you think I helped, Please mark brainliest! Would really appreciate!

4 0
2 years ago
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