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sergejj [24]
3 years ago
15

You have cards with the letters A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P. Event U is choosing the cards A, B, C

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
5 0

Answer:

If you are asking how many events use P: 1 event is using the letter P (event W)

Step-by-step explanation:

Why event U cannot be using P: This event is only using the letters A, B, C, and D.

Why event V cannot be using P: This event is only using vowels (A, E, I, O, U)

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A water trough is 9 m long and has a cross-section in the shape of an isosceles trapezoid that is 20 cm wide at the bottom, 70 c
ella [17]

Answer:

dv = surface area * dh

so

dv/dt = surface area * dh/dt

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= 40 + 30 = 70 cm = 0.70 m

so

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so

.3 m^3/min = 6.3 m^2 * dh/dt

and

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Step-by-step explanation:

7 0
2 years ago
How do you get the answer to 10+12y=2y+40
stepladder [879]
Y = 3

Exp:

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2 years ago
What is “ f(x) = 2x^2- 32x” in standard form if it has one?
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3 years ago
42 is how many groups of 7?
erica [24]
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4 0
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Read 2 more answers
Evaluate the following integrals: 1. Z x 4 ln x dx 2. Z arcsin y dy 3. Z e −θ cos(3θ) dθ 4. Z 1 0 x 3 √ 4 + x 2 dx 5. Z π/8 0 co
Zigmanuir [339]

Answer:

The integrals was calculated.

Step-by-step explanation:

We calculate integrals, and we get:

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4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}

5)  \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=

=\frac{3π+8}{64}

6)  ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x

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6 0
3 years ago
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