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kotykmax [81]
3 years ago
5

Part 4. Find the missing sides for the 30 60 90 triangles. Please show work for each​

Mathematics
2 answers:
inna [77]3 years ago
7 0

10. tan(30) = l / 6√3

l = tan(30) x 6√3

l = 6

cos(30) = 6√3 / y

y =  6√3/cos(30)

y = 12

11. tan(30) = c/30

c = 30 x tan(30)

c = 10√3

cos(30) = 27/w

w = 27/cos(30)

w = 18√3

12.

sin(60) = 36/y

y = 36/sin(60)

y = 24√3

tan(60) = 36/x

x = 36/tan(60)

x = 12√3

tatuchka [14]3 years ago
3 0

Answer:

  10. (l, y) = (6, 12)

  11. (c, w) = (9√3, 18√3)

  12. (x, y) = (12√3, 24√3)

Step-by-step explanation:

Side ratios, shortest to longest, in a 30°-60°-90° triangle are ...

  1 : √3 : 2

__

10. l : 6√3 : y = 1 : √3 : 2

multiply by 6

  = 6 : 6√3 : 12

  l = 6, y = 12

__

11. c : 27 : w = 1 : √3 : 2

multiply by 27/√3 = 9√3

  = 9√3 : 27 : 18√3

  c = 9√3, w = 18√3

__

12. x : 36 : y = 1 : √3 : 2

multiply by 36/√3 = 12√3

  = 12√3 : 36 : 24√3

  x = 12√3, y = 24√3

__

This is easier when the triangle is drawn to clearly differentiate the lengths of the sides. The long leg is opposite the 60° angle; the short leg is opposite the 30° angle.

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Consider the line y = 7x-9.
KatRina [158]

y = \frac{-1}{7}x -\frac{8}{7} is the equation of the line that is perpendicular to this line and passes through the point (6, -2)

y = 7x - 44 equation of the line that is parallel to this line and passes through the point (6, -2)

<em><u>Solution:</u></em>

<em><u>Given that line is:</u></em>

y = 7x - 9

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + b ------ eqn 1

Where, "m" is the slope of line and "b" is the y intercept

On comparing eqn 1 with y = 7x - 9 we get,

m = 7

<h3><u>Find the equation of the line that is perpendicular to this line and passes through the point (6, -2)</u></h3>

We know that,

Product of slope of a line and slope of line perpendicular to given is always -1

Therefore,

7 \times \text{ slope of line perpendicular to it } = -1\\\\\text{ slope of line perpendicular to it } = \frac{-1}{7}

Now find the equation of line:

\text{ Substitute } m = \frac{-1}{7} \text{ and } (x, y) = (6, -2) \text{ in eqn 1}

-2 = \frac{-1}{7} \times 6 + b\\\\-2 = \frac{-6}{7} + b\\\\b = -2+\frac{6}{7}\\\\b = \frac{-14+6}{7}\\\\b = \frac{-8}{7}

\text{Substitute } m = \frac{-1}{7} \text{ and } b = \frac{-8}{7} \text{ in eqn 1}\\\\y = \frac{-1}{7}x -\frac{8}{7}

Thus the equation of line perpendicular to given line is found

<h3><u>Find the equation of the line that is parallel to this line and passes through the point (6, -2)</u></h3>

Slopes of parallel lines are equal

Therefore,  m = 7

<em><u>Substitute m = 7 and (x, y) = (6, -2) in eqn 1</u></em>

-2 = 7(6) + b

-2 = 42 + b

b = -44

<em><u>Substitute m = 7 and b = -44 in eqn 1</u></em>

y = 7x - 44

Thus equation of line parallel to given line is found

8 0
3 years ago
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