Answer:
a) 9%
, not unusual
b) 42.4%
c) 48.4%
d) 11.1%
, 44.4%
, 44.4%
Step-by-step explanation:
We have the following information from the statement:
n = 12
r = 4
a)
P (likebothofthem) = P (likefirstsong) * P (likesecondsong)
P = 4/12 * 3/11
P = 0.09 = 9%
The probability is not unusual, unusual is considered less than 0.05 or 5%
b)
P (likeneither) = P (notlikefirstsong) * P (notlikesecondsong)
P = 8/12 * 7/11
P = 0.424 = 42.4%
c) P (likeexactlyoneofthem) = P (firstsongliked) * P (secondsongnotliked) + P (firstsongnotliked) * P (secondsongliked)
P = (4/12 * 8/11) + (8/12 * 4/11)
P = 0.484 = 48.4%
d)
a)
P (likebothofthem) = P (likefirstsong) * P (likesecondsong)
P = 4/12 * 4/12
P = 0.111 = 11.1%
The probability is not unusual, unusual is considered less than 0.05 or 5%
b)
P (likeneither) = P (notlikefirstsong) * P (notlikesecondsong)
P = 8/12 * 8/12
P = 0.444 = 44.4%
c) P (likeexactlyoneofthem) = P (firstsongliked) * P (secondsongnotliked) + P (firstsongnotliked) * P (secondsongliked)
P = (4/12 * 8/12) + (8/12 * 4/12)
P = 0.444 = 44.4%
They have different masses
The attendance at twenty-five high school football games was: 250, 400, 350, 750, 200, 1000, 1200, 800, 600, 900,
wolverine [178]
Answer:
B and d
Step-by-step explanation:
Brainliest pls.
Answer:
The 99% confidence interval for the true mean number of reproductions per hour for the bacteria is between 9.6 and 10.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 9.8 - 0.2 = 9.6 reproductions per hour.
The upper end of the interval is the sample mean added to M. So it is 9.8 + 0.2 = 10 reproductions per hour.
The 99% confidence interval for the true mean number of reproductions per hour for the bacteria is between 9.6 and 10.