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Blababa [14]
3 years ago
13

What is 20-4? My brother doesnt believe that the answer is 25 and he keeps saying its 16 please tell me i am correct

Mathematics
2 answers:
Ilya [14]3 years ago
4 0

Answer:

you're correct

Step-by-step explanation:

babymother [125]3 years ago
3 0

Answer:

Dont tell me you're trolling. Anyway, its 16

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What is the range of the function f(x)=7-3x when the domain is {-4, -2, 0, 2}?
klemol [59]

Answer:

{19,13,7,1}

Step-by-step explanation:

Since the domain is the input we have to plug in each of those numbers to get the range ( or the output.) When we plug in -4 we get 19. When we plug in -2 we get 13, when we plug in 0 we get 7 and when we plug in 2 we get 1. (:

6 0
3 years ago
What is −30−6r= -36 ?
Nadya [2.5K]

-30-6r=36

We move all terms to the left:

-30-6r-(36)=0

We add all the numbers together, and all the variables

-6r-66=0

We move all terms containing r to the left, all other terms to the right

-6r=66

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7 0
3 years ago
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Write an equation in point-slope form of the line with slope –8 that contains the point j(–3, 2).
patriot [66]
The point-slope formula is y-y1=m(x-x1). You will then substitute into this equation. The answer will be y-2=-8(x+3).
4 0
4 years ago
Challenge #1
o-na [289]

Answer:

Translate 10 units right, 9 units up

Step-by-step explanation:

translations simply take the image and move it up or down or side to side, reflections flip the image, dilation changes the dimensions of an image, and rotation rotates an image on its origin point.

8 0
3 years ago
Jacob consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Jacob's body
sasho [114]

Answer: 0.87400mg of caffeine.

Step-by-step explanation:

You have

N(t)=N0(e^−rt)(1)

as a general Exponential decay equation where N0 is the amount at t=0, N(t) is the amount remaining at time t and r is the exponential decay constant. You're specifically given that after 10 hours, the decay factor is 0.2601, i.e.,

N(10)/N(0)=N0(e^−10r)/N0(e^0)= e^−10r=0.2601 . .(2)

Taking the last 2 parts of (2) to the power of 0.1t gives

e^−rt=0.2601^.1t . .(3)

This means that

N(t)=N0(e^−rt)=N0(0.2601^.1t). .(4)

Also,

N(2.56)N(1.56)=N0(0.2601.1(2.56))N0(0.2601.1(1.56))=0.2601.1(2.56−1.56)=0.2601^.1

= 0.87400mg of caffeine.

6 0
3 years ago
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