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Genrish500 [490]
3 years ago
10

Help me please yall are basically the best

Mathematics
1 answer:
egoroff_w [7]3 years ago
6 0

Answer:

4 i think

Step-by-step explanation:

You might be interested in
Erin buys a bag of peanuts that weighs 3/4 of a pound.later that week the bag is 2/3 full how much does the back of peanuts weig
nasty-shy [4]

The answer is 1/2lbs, here's how.


3/4x2/3=6/12 reduced to 1/2lbs.

4 0
2 years ago
"A rectangle has a height of 5 cm and its base is increasing at a rate" of 3/2 cm/min. When its area is 60 cm2, at what rate is
sukhopar [10]

Answer:

The diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

Step-by-step explanation:

Dimensions of the rectangle

Height = 5cm

Rate of base = 3/2 cm/min

Area = 60cm^2

We know the area of a rectangle of given by = base* Height

b*h = 60

b*5 = 60

b = 12cm

Applying Pythagoras theorem while drawing a diagonal to the rectangle

  b^2 +h^2 =  D^2\\

 5^2 +12^2 = 13^2

so our diagonal will be 13cm  

Upon differentiating the area of the rectangle  we get

b*h = A=60cm^2

using  the chain rule of differentiation

h*db/dt + b*dh/dt  = 0

b*dh/dt = -h*db/dt

12*dh/dt = -5*3/2

dh/dt = -5/8 cm//min

so the height of the rectangle is decreasing at the rate of -5/8cm/min

now we have all the measurements we need

b = 12 , db/dt = 3/2cm/min

h = 5 , dh/dt = -5/8 cm/min

b^2 +h^2  = D^2

Upon differentiating we get

2b*db/dt + 2h*dh/dt = 2D*dD/dt

b*db/dt + h*dh/dt = D*dD/dt

12*3/2 + 5*(-5/8) = 13*dD/dt

18 -25/8 = 13*dD/dt

\frac{144-25}{8} = 13*dD/dt

dD/dt = \frac{119}{104} cm/min

Therefore the diagonal is increasing at the rate of 119/104cm/min of the given rectangle.

6 0
3 years ago
Please help! How on earth do I do this? In the year 2015, Anna bought a new car for $36,000. In 2017, she was told that the valu
Klio2033 [76]

Part A

Purchase Value of Anna's Car in 2015 = $36,000

Depreciated Value of Anna's Car in 2017 = $25,000

We know that the value of the car is depreciating linearly.


From the above data, we can see that the value of the car has reduced by $36,000-$25,000 = $11,000 over 2 years.

⇒ Per year the value has been depreciated by \frac{11000}{2}

⇒ Per year the value has been depreciated by $5,500

So if the value of a car in 2015 is V₀ then value of the car after t years can be determined by the below function:

V (t) = V₀ - (t*5,500), where t indicates the years passed since 2015

OR V (t) = 36,000 - (t*5,500), where t indicates the years passed since 2015

Part B

Suggested value of Anna's car for trade in option in 2018 = $15,000

In 2018, 3 years would have been passed since 2015. Using the value of t = 3 in the function determined in Part A:

V(3) = V₀ - (3*5,500)

⇒ V(3) = 36,000 - (16,500)

⇒ V(3) = $19,000

From the above calculations, we can see that the value of the car in 2018 should be $19,000, however the suggested value for trade in is indicated as $15,000 which is lower than what the value of the car should be. Hence, basis linear depreciation, the $15,000 value is not fair for the car in 2018.

3 0
2 years ago
Help please lol soon
Yuliya22 [10]

Answer:

d.

D: {-7, 0, 2, 6}

R: {-13, 0, 5, 13}

Step-by-step explanation:

Domain of a relation is the set of all input values (x-values) while the range is the set of all corresponding output values (y-values) in a given relation.

Given the relation represented by the table above,

Domain would be: {-7, 0, 2, 6}

Range: {-13, 0, 5, 13}

5 0
3 years ago
-6=x/8+4 what is the value of x?
taurus [48]

Answer:

  -80

Step-by-step explanation:

Subtract 4:

  -10 = x/8

Multiply by 8:

  -80 = x

The value of x is -80.

_____

This sort of equation is sometimes referred to as a "two-step" linear equation.

<u>Step 1</u>. After you identify the term containing the variable (x/8), you identify any constants on the same side of the equal sign (+4). Add their opposite to both sides of the equation. That gets the variable term by itself.

<u>Step 2</u>. Then identify the coefficient of the variable (1/8). Multiply both sides of the equation by the reciprocal of this value. That will make the coefficient of the variable become 1. The constant on the other side of the equal sign is now the value of the variable.

6 0
3 years ago
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