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astraxan [27]
3 years ago
6

Of 60 corn seeds that were planted, 18 of them did not sprout. What percent of the corn seeds

Mathematics
2 answers:
tekilochka [14]3 years ago
7 0

Answer:

The percent of the the corn seeds is 30%.

Step-by-step explanation:

Because when you calculate 60% and 18% will get a percent 30%.

Solution for 18 is what percent of 60:

18:60*100 =

( 18*100):60 =

1800:60 = 30

Now we have: 18 is what percent of 60 = 30

Question: 18 is what percent of 60?

Percentage solution with steps:

Step 1: We make the assumption that 60 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that $100\%=60$.

Step 4: In the same vein, $x\%=18$.

Step 5: This gives us a pair of simple equations:

$100\%=60(1)$.

$x\%=18(2)$.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{60}{18}$

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{18}{60}$

$\Rightarrow x=30\%$

Therefore, $18$ is $30\%$ of $60$.

Hope this helps :D and can i get brainlest plz

Lyrx [107]3 years ago
4 0

Answer:

30%

Step-by-step explanation:

18 / 60 = .3 * 100 = 30%

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Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

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13 are hearts.

13 are clubs.

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2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

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(b)Flush: five cards of the same suit but different values, for example:

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(c)Full house: A three of a kind and a pair, for example:

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So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899

So 2899 possible ways.

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