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astraxan [27]
3 years ago
6

Of 60 corn seeds that were planted, 18 of them did not sprout. What percent of the corn seeds

Mathematics
2 answers:
tekilochka [14]3 years ago
7 0

Answer:

The percent of the the corn seeds is 30%.

Step-by-step explanation:

Because when you calculate 60% and 18% will get a percent 30%.

Solution for 18 is what percent of 60:

18:60*100 =

( 18*100):60 =

1800:60 = 30

Now we have: 18 is what percent of 60 = 30

Question: 18 is what percent of 60?

Percentage solution with steps:

Step 1: We make the assumption that 60 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that $100\%=60$.

Step 4: In the same vein, $x\%=18$.

Step 5: This gives us a pair of simple equations:

$100\%=60(1)$.

$x\%=18(2)$.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{60}{18}$

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{18}{60}$

$\Rightarrow x=30\%$

Therefore, $18$ is $30\%$ of $60$.

Hope this helps :D and can i get brainlest plz

Lyrx [107]3 years ago
4 0

Answer:

30%

Step-by-step explanation:

18 / 60 = .3 * 100 = 30%

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A company makes 120 bags.
Vera_Pavlovna [14]

Answer:

7/15

Step-by-step explanation:

You have 120 bags. 64 of them in total do not contain buttons.

120 - 64 = 56

You have 56 bags with buttons. The simple answer is,

56/120

You can simplify this down to 7/15

If you're looking for percent, the answer is 46.67%

5 0
2 years ago
You believe the population is normally distributed. Find the 80% confidence interval. Enter your answer as an open-interval (i.e
victus00 [196]

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = \dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}

mean = 15.58

the standard deviation \sigma = \sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}

the standard deviation = \sqrt{\dfrac{(26.2  - 15.58)^2 +(27.7 - 15.58)^2 +(8.6  - 15.58)^2 + (3.8  - 15.58)^2  + (11.6  - 15.58)^2  }{5 }  }

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E = t \times \dfrac{\sigma}{\sqrt{n}}

The Margin of Error M.O.E = 1.533 \times \dfrac{9.62297}{\sqrt{5}}

The Margin of Error M.O.E = 1.533 \times 4.3035

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( \mu  \pm M.O.E )

The  Confidence interval = ( \mu  +  M.O.E , \mu - M.O.E )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)

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C. 196 sq. In.

Multiply 4×7×7 To find the surface area.

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