The sum of 5 times a number and -8:
5x - 8 = y
your answer would be A. I would hope this is right
Answer:
where 
= 2
Step-by-step explanation:
512/-8 = -64
difference of n = 3
![\sqrt[3]{64} = 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%3D%204)
where = 2
Answer:
The answer is 15
Step-by-step explanation:
I know and is not stupid
Answer:
see explanation
Step-by-step explanation:
To find the zeros let p(x) = 0 , that is
(x² - 1)(x² - 5x + 6) = 0
Factorise each factor
x² - 1 ← is a difference of squares and factors as (x - 1)(x + 1)
x² - 5x + 6 = (x - 2)(x - 3), thus
(x - 1)(x + 1)(x - 2)(x - 3) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
x + 1 = 0 ⇒ x = - 1
x - 2 = 0 ⇒ x = 2
x - 3 = 0 ⇒ x = 3
The zeros are x = ± 1, x = 2, x = 3
