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Lady bird [3.3K]

2 years ago

10

TRUE or FALSE? When plotting a point on a coordinate plane, the first number in a coordinate pair tells you the number of spaces

to move across the x-axis, while the second number tells you the number of spaces to move across the y-axis. (yes i am dumb)

1 answer:

Luda [366]2 years ago

7 0

Answer:

True

Step-by-step explanation:

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I need help on this one

mel-nik [20]

Answer: 4/9

Step-by-step explanation:

apply product rule to 2/3 2^2 / 3^2

7 0

2 years ago

Jamar is buying bottles of juice for his his class party A pack of 12 bottles of juice cost $3.96 determine the cost of 1 bottle

NeX [460]

Answer: The cost of 1 bottle of juice is $0.33 or 33 cents.

Step-by-step explanation: Divide the total cost by the amount of bottles of juice to find how much each bottle costs.

$\frac{3.96}{12}$ = 0.33

7 0

3 years ago

Simplify the expression state any excluded values<br> 2a^2-4a+2<br> ---------------<br> 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

3 years ago

WILL MARK BRAINLEIST PLEASE HURRY

Marina86 [1]

Answer:

<h3>The reason which is incorrect is in Step 2 and reason 2</h3>

Step-by-step explanation:

Given that Logan's equation is $\frac{3}{2}\times (x-10)=50$

<h3>To simplify and find the which reason is incorrect :</h3>

Logan's solution and reasoning for solving an equation are shown below:

Step1 $\frac{3}{2}\times (x-10)=50$

Reason 1: Given

Step2 $\frac{3}{2}\times x-10+10=50+10$

Reason 2: Addition Property of Equality

Step3 $\frac{3}{2}\times x=60$

Reason 3: Simplify

Step4 $\frac{3}{2}\times x \times (\frac{2}{3})=60\times (\frac{2}{3})$

Reason 4: Division Property of Equality

Step5 $x=40$

Reason 5: Simplify

<h3>The reason which is incorrect is in Step 2 and reason 2</h3><h3>The corrected steps are</h3>

Step1 $\frac{3}{2}\times (x-10)=50$

Reason 1: Given

Step2 $\frac{3}{2}\times (x)-\frac{3}{2}\times (10)=50$

Reason 2: Distributive property

Step3 $\frac{3}{2}\times x-15=60$

Reason 3: Simplify

Step4 $\frac{3}{2}\times x-15+15=50+15$

Reason 4: Addition Property of Equality

Step5 $\frac{3}{2}\times x=65$

Reason 5: Simplify

Step6 $\frac{3}{2}\times x \times (\frac{2}{3})=65\times (\frac{2}{3})$

Reason 6: Division Property of Equality

Step7 $x=\frac{130}{3}$

Reason 7: Simplify

<h3 />

5 0

3 years ago

Solve for x: 3x²-243<br>

mylen [45]

3x²–243=0 —> 3 (x²–81) = 0 —>

x²–81=0 —> (x-9)(x+9)=0

x-9=0 —> x=9

x+9=0 —> x=–9

I hope I helped you^_^

7 0

2 years ago