Answer:
The cost of the old ball was $100.
Step-by-step explanation:
The cost of the new ball = $300
The new ball has three times the price of his old ball.
So, let the price of the old ball be = x
As per situation, we get the equation:
Dividing both sides by 3:
=> x = 100
Hence, the cost of the old ball was $100.
dC = 2.44
Relative error = 19%
Δv = 3 ; ΔT = 1 , v = 23, T = 8
Use differential Calculus
Relative Error
dC / C @(T = 8, v=23) * 100 = 19 %
3,2
18,12
18/6 = 3
12/6 = 2
so
srry its timed so i tried to be quick