3 years ago

Help please help me. ????????????????????????????????????

Mathematics

1 answer:

jek_recluse [69]3 years ago

6 0

I believe its B and D

You might be interested in

Find the coordinates of the point on the unit circle measured 3 units clockwise along the circumference of the circle from (1, 0

Virty [35]

I'm in high school so you're screwed

8 0

3 years ago

Find a point-slope form for the line with slope 1/5 and passing through the point (-7,-6).

KiRa [710]

The equation for this would be:
y+6= 1/5(x+7)

5 0

3 years ago

Find x in the given figures. Thanks in advance! xD

docker41 [41]

Answer:

x=8 an they are at the exact opposite side

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which score has a higher relative position, a score of 38 on a test for which = 27 and s = 10, or a score of 262.7 on a test for

Vikentia [17]

I want to help you but please make it easier to understand

4 0

4 years ago

How can csc^2-cot^2 = 1?

Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

$\csc^{2} (x) - \cot^{2} (x) = 1$

Take the left hand side and simplify to get the right hand side.

$\csc^{2} (x) - \cot^{2} (x) = \frac{1}{\sin^{2} (x)} - \frac{ \cos^{2} (x)}{\sin^{2} (x)}$

Collect LCM for the denominators.

$\csc^{2} (x) - \cot^{2} (x) = \frac{1 - \cos^{2} (x)}{\sin^{2} (x)}$

Recall the Pythagorean Identity.

$\cos^{2} (x) + \sin^{2} (x) = 1$

This implies that:

$1 - \cos^{2} (x) = \sin^{2} (x)$

We substitute this to get,

$\csc^{2} (x) - \cot^{2} (x) = \frac{\sin^{2} (x)}{\sin^{2} (x)}$

$\csc^{2} (x) - \cot^{2} (x) = 1$

6 0

3 years ago