Answer:
The dimensions of the rectangular volleyball court are 60 ft x 30 ft
Step-by-step explanation:
Let
x ----> the length of rectangular volleyball court
y ---> the width of the rectangular volleyball court
we know that
The area of the rectangular volleyball court is equal to
![A=xy](https://tex.z-dn.net/?f=A%3Dxy)
![A=1,800\ ft^2](https://tex.z-dn.net/?f=A%3D1%2C800%5C%20ft%5E2)
so
----> equation A
-----> equation B
substitute equation B in equation A
![1,800=(2y)y](https://tex.z-dn.net/?f=1%2C800%3D%282y%29y)
![1,800=2y^2](https://tex.z-dn.net/?f=1%2C800%3D2y%5E2)
Solve for y
Simplify
![900=y^2](https://tex.z-dn.net/?f=900%3Dy%5E2)
take square root both sides
![y=30\ ft](https://tex.z-dn.net/?f=y%3D30%5C%20ft)
<em>Find the value of x</em>
![x=2y](https://tex.z-dn.net/?f=x%3D2y)
substitute the value of y
![x=2(30)=60\ ft](https://tex.z-dn.net/?f=x%3D2%2830%29%3D60%5C%20ft)
therefore
The dimensions of the rectangular volleyball court are 60 ft x 30 ft
Answer:
no soulition
Step-by-step explanation:
I think I’ve done this right maybe not but.
9). -0.35
I don’t know 10
Answer:
its april fools
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
please mark brainliest