Question

Factorize x^2/16+xy+4y^2​

Answer 1

Answer:

$\frac{x^2}{16} +xy+4y^2$ can be factored out as: $(\frac{x}{4} +2\,y)^2$

Step-by-step explanation:

Recall the formula for the perfect square of a binomial :

$(a+b)^2=a^2+2ab+b^2$

Now, let's try to identify the values of $a$ and $b$ in the given trinomial.

Notice that the first term and the last term are perfect squares:

$\frac{x^2}{16} = (\frac{x}{4} )^2\\4y^2=(2y)^2$

so, we can investigate what the middle term would be considering our $a=\frac{x}{4}$, and $b=2y$:

$2\,a\,b=2\,(\frac{x}{4}) \,(2\,y)=x\,y$

Therefore, the calculated middle term agrees with the given middle term, so we can conclude that this trinomial is the perfect square of the binomial:

$(\frac{x}{4} +2\,y)^2$