Question

Find the median, first quartile, third quartile, and interquartile range of the data.

Answer 1

Answer:

Median: 189.5

First quartile: 181.5

Third quartile: 203.75

Interquartile Range: 22.25

Step-by-step explanation:

To find the median, first quartile and third quartile we need to organize the data as:

157, 181, 183, 189, 190, 203, 204, 212

Now, the position of the median is calculated as:

$PosM = (n+1)*\frac{1}{2}$

Where n is 8, so replacing we get:

$PosM = (8+1)*\frac{1}{2}=4.5$

So, the median can be calculated as:

Median = 0.5(189) + 0.5(190) = 189.5

Because 189 is in the fourth position and 190 is in the first position.

At the same way the position for the first and third quartile is:

$PosQ1 = (n+1)*\frac{1}{4}= (8+1)*\frac{1}{4}=2.25\\PosQ3 = (n+1)*\frac{3}{4}= (8+1)*\frac{3}{4}=6.75$

Then, the first and third quartile is equal to:

Q1 = 0.75(181) + 0.25(183) =181.5

Q3 = 0.25(203) + 0.75(204) = 203.75

Where 181 is in the second position, 183 is the third position, 203 is the sixth position and 204 is the seventh position.

Finally, the interquartile range is calculated as:

Q3 - Q1 = 203.75 - 181.5 = 22.25