Answer: Search File Explorer: Open File Explorer from the taskbar or right-click on the Start menu, and choose File Explorer, then select a location from the left pane to search or browse. For example, select This PC to look in all devices and drives on your computer, or select Documents to look only for files stored there.
Explanation: hope this helps :)
Answer:
In Python:
N = int(input("Positive integer: "))
if N > 0:
flag = False
for i in range(1,N+1):
if i * i == N:
flag = True
break
print(str(flag))
else:
print("Positive integer only")
Explanation:
N = int(input("Positive integer: "))
If the number is positive
if N > 0:
This initializes a boolean variable to false
flag = False
This iterates from 1 to the input integer
for i in range(1,N+1):
This checks if th number is a square of some integer
if i * i == N:
If yes, flag is set to true
flag = True
The loop is exited
break
This prints either true or false, depending on the result of the loop
print(str(flag))
If otherwise, that the number is not positive
<em>else:</em>
<em> print("Positive integer only")</em>
Answer:
.
Explanation:
you do to me on the bottom bar and once you hit that you click the pencil and change it
Answer:
t= 8.7*10⁻⁴ sec.
Explanation:
If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.
As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.
Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:
If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:
⇒ t = 8.7*10⁻⁴ sec.
Answer:
see explanation
Explanation:
Carlos can make a copy of the old presentation that preserves all the formatting, and replace old content with new information.
