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3 years ago

11

Please help. 40 points

1 answer:

Natasha_Volkova [10]3 years ago

5 0

Answer:

number 2

Step-by-step explanation:

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Q # 4 Simplify the product

timama [110]

For this case we have the following product:
$(x-4) (x + 3)
$
We must use the distributive property correctly to solve the problem.
We have then:
$x ^ 2 + 3x - 4x - 12
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Then, we must add similar terms.
We have then:
$x ^ 2 - x - 12
$
Answer:
The final product is given by:
$x ^ 2 - x - 12
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option 2

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3 years ago

Three circular arcs of radius units bound the region shown. Arcs and are quarter-circles, and arc is a semicircle. What is the a

mestny [16]

Answer:

Three circular arcs of radius $5$ units bound the region shown. Arcs $AB$ and $AD$ are quarter-circles, and arc $BCD$ is a semicircle.

Step-by-step explanation:

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2 years ago

Please answer #1 for me only ! What is my Y for #1 , don't forget to graph !

mart [117]

The table and the graph is shown in the following picture

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3 years ago

Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the

ANTONII [103]

Answer:

Length of right-angle triangle 'a' = 4

b)

<u><em></em></u> $sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$ <u><em></em></u>

<u><em></em></u> $cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$ <u><em></em></u>

<u><em></em></u> $tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$ <u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given b = 3 and hypotenuse c = 5

Given ΔABC is a right angle triangle

By using pythagoras theorem

c² = a² + b²

⇒ a² = c² - b²

⇒ a² = 5²-3²

=25 - 9

a² = 16

⇒ a = √16 = 4

The sides of right angle triangle a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u> $sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$ <u><em></em></u>

<u><em></em></u> $cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$ <u><em></em></u>

<u><em></em></u> $tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$ <u><em></em></u>

7 0

3 years ago

What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1, 5)? y = - 2y = -3x + 7 2x + 3y -

Karolina [17]

The line passing through (3, -1) and (-1, 5) has this slope:

5+1

m = ---------- = -3/2

-1-3

We need to find the y-intercept. To do this, substitute the knowns (-3/2 for m, -1 for y and 3 for x) into the slope-intercept equation:

-1 = (-3/2)(3) + b. Then: -1 = -9/2 + b, and so b = 9/2 - 1 = 7/2.

The desired equation is y = (-3/2)x + 7/2.

8 0

3 years ago

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