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gtnhenbr [62]
3 years ago
15

Which calculation will ALWAYS have a result greater than 1?

Mathematics
1 answer:
stepladder [879]3 years ago
4 0
1 3/4-a fraction less than 3/4
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Plz I need help on #12
Lorico [155]

Answer:

C its C

Step-by-step explanation:

7 0
3 years ago
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Sociologists say that 85% of married women claim that their husband's mother is the biggest bone of contention in their marriage
hoa [83]

Answer:

(A) 0.377,

(B) 0.000,

(C) 0.953,

(D) 0.047

Step-by-step explanation:

We assume that having a bone of intention means not liking one's Mother-in-Law

(A) P(all six dislike their Mother-in-Law) = (85%)^6 = (.85)^6 = 0.377

(B) P(none of the six dislike their Mother-in-Law) =

(100% - 85%)^6 =

0.15^6 =

0.000

(C) P(at least 4 dislike their Mother-in-Law) =

P(exactly 4 dislike their Mother-in-Law) + P(exactly 5 dislike their Mother-in-Law) + P(exactly 6 dislike their Mother-in-Law) =

C(6,4) * (.85)^4 * (1-.85)^2 + C(6,5) * (.85)^5 * (.15)^1 + C(6,6) * (.85)^6 = (15) * (.85)^4 * (.15)^2 + (6) * (.85)^5 * .15 + (1) * (.85)^6 =

0.953

(D) P(no more than 3 dislike their Mother-in-Law) =

P(exactly 0 dislikes their Mother-in-Law) + P(exactly 1 dislikes her Mother) + P(exactly 2 dislike their Mother-in-Law) + P(exactly 3 dislike their Mother-in-Law) =

C(6,0) * (.85)^0 * (.15)^6 + C(6,1) * (.85)^1 * (.15)^5 + C(6,2) * (.85)^2 * (.15)^4 + C(6,3) * (.85)^3 * (.15)^3 =

(1)(1)(.15)^6 + (6)(.85)(.15)^5 + (15)(.85)^2 *(.15)^4 + (20)(.85)^3 * (.15)^3 =

0.047

3 0
3 years ago
I need help please ??
Genrish500 [490]

Answer with step-by-step explanation:

Equation: x × 4 = y

This equation is true because if you look at the graph, multiply 4 by each x length and you will get the y length.

Hope this helped!

8 0
3 years ago
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Tara combines 7.49 ounces of strawberries with 6.26 ounces of blueberries to make fruit bowls. She pours the fruit equally into
kupik [55]

Answer:

3.33 ounces in each bowl

Step-by-step explanation:

7.49 + 6.26 = 13.75

subtract 0.43 and that equals 13.32

13.32 ÷ 4 = 3.33

I hope this helped :/

6 0
3 years ago
Mateo is constructing an equilateral triangle inscribed in a circle with center P. He draws the diameter of the circle through c
spin [16.1K]
<span>Let,
diameter = segment AB through center P.
Set the compass to the radius PB, at B and draw two little arcs that intersect the circumference of the circle at C and D.
Then Triangle ACD will be an equilateral triangle inscribed in the given circle.
Hence,
The right option is :
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