What is 8 7/10 as an improper fraction

Mathematics

1 answer:

Kobotan [32]2 years ago

8 0

8 7/10 as a improper fraction is 87/10

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A population of values has a normal distribution with μ = 155.4 and σ = 49.5 . You intend to draw a random sample of size n = 24

xz_007 [3.2K]

Answer:

(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.

(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.

Step-by-step explanation:

Let the random variable X follow a Normal distribution with parameters μ = 155.4 and σ = 49.5.

(a)

Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:

$P(158.6 < X$

*Use a standard normal table.

Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.

(b)

A sample of n = 246 is selected.

Compute the probability that a sample mean is between 158.6 and 159.2 as follows:

$P(158.6 < \bar X$

*Use a standard normal table.

Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.

4 0

3 years ago

Read 2 more answers

Jay spent ten more than three times the number of hours on his science fair project than jamie spent on her project jay spent 43

Aliun [14]

Why did both of their names have to start with the same letter

x=jay hours
y=jamie huours

x=10+3y
x=43

so
43=10+3y
minus 10
33=3y
divide 3
11=y

jamies spent 11 hours

8 0

3 years ago

Mrs. Smith's class is working on a variety of science experiments. Each

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

If there are n students, then the number of pairs is $\frac{n(n-1)}{2}$ .

With 12 students, $\frac{12(12-1)}{2} = \frac{132}{2}=66$ pairs can be formed.

The reason the formula works is this: Each of the 12 students can be paired with 11 other students (no student is paired with him/her self). But counting 12 x 11 = 132 counts each pair twice. Example: student A can be paired with student B,..., student B can be paired with student A. The pair was counted two times.

See the attached image that shows pairings of 5 students. There are

5(5 - 1)/2 = 5(4)/2 = 10 pairs.